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zimovet [89]
3 years ago
9

Uhm mainly 11 and 12 but if u solve all of them I’ll give u brainliest

Mathematics
1 answer:
Dvinal [7]3 years ago
3 0

                                             Question 11)

Answer:

\log _2\left(63\right)-\log _2\left(9\right)=\log _2\left(7\right)=2.80

Step-by-step explanation:

Given the expression

\log _2\left(63\right)-\log _2\left(9\right)

\mathrm{Apply\:log\:rule}:\quad \log _c\left(a\right)-\log _c\left(b\right)=\log _c\left(\frac{a}{b}\right)

\log _2\left(63\right)-\log _2\left(9\right)=\log _2\left(\frac{63}{9}\right)

=\log _2\left(\frac{63}{9}\right)

\mathrm{Divide\:the\:numbers:}\:\frac{63}{9}=7

=\log _2\left(7\right)

=2.80

Therefore,

\log _2\left(63\right)-\log _2\left(9\right)=\log _2\left(7\right)=2.80

                                            Question 12)

Answer:

\log \:_2\left(3\right)+\log \:_2\left(15\right)-\log \:_2\left(9\right)=\log \:_2\left(5\right)=2.32    

Step-by-step explanation:

Given the expression

\log _2\left(3\right)+\log _2\left(15\right)-\log _2\left(9\right)

\mathrm{Apply\:log\:rule}:\quad \log _c\left(a\right)+\log _c\left(b\right)=\log _c\left(ab\right)

\log _2\left(3\right)+\log _2\left(15\right)=\log _2\left(3\cdot \:15\right)

=\log _2\left(3\cdot \:15\right)-\log _2\left(9\right)

\mathrm{Multiply\:the\:numbers:}\:3\cdot \:15=45

=\log _2\left(45\right)-\log _2\left(9\right)

\mathrm{Apply\:log\:rule}:\quad \log _c\left(a\right)-\log _c\left(b\right)=\log _c\left(\frac{a}{b}\right)

\log _2\left(45\right)-\log _2\left(9\right)=\log _2\left(\frac{45}{9}\right)

=\log _2\left(\frac{45}{9}\right)

\mathrm{Divide\:the\:numbers:}\:\frac{45}{9}=5

=\log _2\left(5\right)

=2.32

Therefore,

\log \:_2\left(3\right)+\log \:_2\left(15\right)-\log \:_2\left(9\right)=\log \:_2\left(5\right)=2.32                            

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<h3>How to reflect a point across an axis?</h3>

For a point (x, y), a reflection across the x-axis gives the point (x, -y), while for a point (x, y) a reflection across the y-axis gives (-x, y).

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brainly.com/question/4289712

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