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2 years ago

Please answer fast!!!!!

Mathematics

2 answers:

BlackZzzverrR [31]2 years ago

6 0

Answer:

x = 2

Step-by-step explanation:

note that 4096 = $8^{4}$ , then

$8^{2x}$ = $8^{4}$

Since bases on both sides are equal, both 8 , then equate the exponents

2x = 4 ( divide both sides by 2 )

x = 2

marishachu [46]2 years ago

4 0

Answer:

x = 2

Step-by-step explanation:

$8^{2x} = 4096$

Step 1 :- Write 4096 in the exponential form with the base of 8.

$8^{2x} = 8^4$

Step 2 :- Since the base of both equation is same , set the exponents equal.

2x = 4

Step 3 :- Divide both side by 2

${2x}{2} = \frac{4 }{2}$

x = 2

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37.

zimovet [89]

Answer:

Step-by-step explanation:

<u>There are total cadies in the bag:</u>

7 + 13 + 5 = 25

<u>Probability of pulling a coffee candy is:</u>

5/25 = 1/5

So each 5th candy should be coffee candy

<u>Then you need to pull at least:</u>

5*3 = 15 candies

<em><u>To ensure 3 coffee candies you would need to pull 25 - 2 = 23 candies</u></em>

5 0

2 years ago

What’s the answer for the photo

Otrada [13]

Be nice if we were sure of the question. I will guess that you want the hypotenuse.

c^2 = a^2 + b^2
a = 6 km
b = 6 km

c^2 = 36 + 36
c^2 = 72
c = sqrt(72)
c = sqrt(9 * 8)
c = 3*sqrt(8)
c = 3 * 2.83
c = 8.49

7 0

2 years ago

LOTS OF POINTS GIVING BRAINLIEST I NEED HELP PLEASEE

Sidana [21]

Answer:

Segment EF: y = -x + 8

Segment BC: y = -x + 2

Step-by-step explanation:

Given the two similar right triangles, ΔABC and ΔDEF, for which we must determine the slope-intercept form of the side of ΔDEF that is parallel to segment BC.

Upon observing the given diagram, we can infer the following corresponding sides:

$\displaystyle\mathsf{\overline{BC}\:\: and\:\:\overline{EF}}$

$\displaystyle\mathsf{\overline{BA}\:\: and\:\:\overline{ED}}$

$\displaystyle\mathsf{\overline{AC}\:\: and\:\:\overline{DF}}$

We must determine the slope of segment BC from ΔABC, which corresponds to segment EF from ΔDEF.

<h2>Slope of Segment BC:</h2>

In order to solve for the slope of segment BC, we can use the following slope formula:

$\displaystyle\mathsf{Slope\:(m)\:=\:\frac{y_2 \:-\:y_1}{x_2 \:-\:x_1}} }$

Use the following coordinates from the given diagram:

Point B: (x₁, y₁) = (-2, 4)

Point C: (x₂, y₂) = ( 1, 1 )

Substitute these values into the slope formula:

$\displaystyle\mathsf{Slope\:(m)\:=\:\frac{y_2 \:-\:y_1}{x_2 \:-\:x_1}}\:=\:\frac{1\:-\:4}{1\:-\:(-2)}\:=\:\frac{-3}{1\:+\:2}\:=\:\frac{-3}{3}\:=\:-1}$

<h2>Slope of Segment EF:</h2>

Similar to how we determined the slope of segment BC, we will use the coordinates of points E and F from ΔDEF to find its slope:

Point E: (x₁, y₁) = (4, 4)

Point F: (x₂, y₂) = (6, 2)

Substitute these values into the slope formula:

$\displaystyle\mathsf{Slope\:(m)\:=\:\frac{y_2 \:-\:y_1}{x_2 \:-\:x_1}}\:=\:\frac{2\:-\:4}{6\:-\:4}\:=\:\frac{-2}{2}\:=\:-1}$

Our calculations show that segment BC and EF have the same slope of -1. In geometry, we know that two nonvertical lines are <u>parallel</u> if and only if they have the same slope.

Since segments BC and EF have the same slope, then it means that $\displaystyle\mathsf{\overline{BC}\:\: | |\:\:\overline{EF}}$ .

<h2>Slope-intercept form:</h2><h3><u>Segment BC:</u></h3>

The <u>y-intercept</u> is the point on the graph where it crosses the y-axis. Thus, it is the value of "y" when x = 0.

Using the slope of segment BC, m = -1, and the coordinates of point C, (1, 1), substitute these values into the <u>slope-intercept form</u> (y = mx + b) to solve for the y-intercept, <em>b. </em>

y = mx + b

1 = -1( 1 ) + b

1 = -1 + b

Add 1 to both sides to isolate b:

1 + 1 = -1 + 1 + b

2 = b

Hence, the <u><em>y-intercept</em></u> of segment BC is: <em>b</em> = 2.

Therefore, the linear equation in <u>slope-intercept form of segment BC</u> is:

⇒ y = -x + 2.

<h3><u /></h3><h3><u>Segment EF:</u></h3>

Using the slope of segment EF, <em>m</em> = -1, and the coordinates of point E, (4, 4), substitute these values into the <u>slope-intercept form</u> to solve for the y-intercept, <em>b. </em>

y = mx + b

4 = -1( 4 ) + b

4 = -4 + b

Add 4 to both sides to isolate b:

4 + 4 = -4 + 4 + b

8 = b

Hence, the <u><em>y-intercept</em></u> of segment BC is: <em>b</em> = 8.

Therefore, the linear equation in <u>slope-intercept form of segment EF</u> is:

⇒ y = -x + 8.

8 0

2 years ago

Mr. Engen rented a car for 35.00 a day and 0.45 a mile . He had the car for 2 days and paid 166.75 . How many miles did he drove

liubo4ka [24]

d = days rented for

m = miles driven for

so the cost of the car is 35 bucks a day and 45 cents or $0.45 per mile driven, let's check it out for say a few days

1st day, 3 miles......................35(1) + 0.45(3)

2nd day, 2 miles..................35(2) + 0.45(2)

3rd day, say 5 miles............35(3) + 0.45(5)

dth day, and m miles..........35d + 0.45m

so the cost function could be written as C = 35d+0.45m.

now, we know for 2 days, d = 2, it cost 166.75 bucks, so

$\bf C=35d+0.45m\implies \stackrel{C}{166.75}=35(\stackrel{d}{2})+0.45m\\\\\\166.75=70+0.45m\implies 96.75=0.45m\\\\\\\cfrac{96.75}{0.45}=m\implies 215=m$

7 0

3 years ago

Hey, can someone help me?

mel-nik [20]

I would go with 115 is the answer you

7 0

3 years ago

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