the value of f(−23) should be 7/3 from my point of view
Answer:
40/3087
Step-by-step explanation:
First, we need to count the number of each type of numbered ball.
Ball Counts: 1 - 5 balls; 2 - 2 balls; 3 - 1 ball; 4 - 2 balls; 5 - 4 balls; 6 - 3 balls; 7 - 1 ball; 8 - 2 balls; 9 - 1 ball, there are then a total of 21 balls
Next, you need to find the probability of each event.
Get less than 4
p(<4) = (5+2+1)/21
p(<4) = 8/21
Get less than 2
p(1) = 5/21
Get exactly 6
p(6) = 3/21
p(6) = 1/7
Next, we need to find the probability of all three events by multiplying the probabilities together.
p(all three) = (8/21)*(5/21)*(1/7)
p(all three) = 40/3087
The probability of all three events occurring is 40/3087.
12 times with a remainder of 1
Yes, is 218cm.
15+16+20+57+20+16+15+16+(57-15-15)+16=218cm
The answer for the second one is 0.
