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vivado [14]
3 years ago
8

On a standardized test, Rasi answered the fast: 22 questions in 5 minutes. There are 7]

Mathematics
1 answer:
kogti [31]3 years ago
7 0

Answer:

they are directly proportional

so

5/22*7=1.59

he would finish in 1.59 min

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A volleyball player sets the ball in the air, and the height of the ball after t seconds is given in feet by h= -16^2+12t+6. A t
pychu [463]

Answer:

Step-by-step explanation:

The given function is

h=-16t^2+12t+6

The graph of this function is a parabola that opens downwards

The line h(t)=8 intersects this parabola, when

t=0.5,t=0.25

The teammate can spike the ball after 0.25 seconds or 0.5 seconds.

The two solutions are reasonable. When the volleyball is accelerating into the air, it passes a height of 8 after 0.25 seconds.

When the ball is dropping after it attains maximum height, it attains another height of 8 after 0.5 seconds again.

8 0
3 years ago
A college has
gladu [14]
Total-107
Male teacher-n
Female teacher-n+23
N+n+23=107
2n+23=107
2n= 84
N=42

Male teacher-42
Female teacher-42+23=65
65/107 teacher are female

8 0
3 years ago
What is x if 4x-79=3x-29
elena-14-01-66 [18.8K]
<em>4x-79=3x-29</em>

<em>Move the terms with "x" on the left, and the numbers on the right.</em>

<em>4x-3x=79-29</em>
<em>x=50</em>
6 0
3 years ago
Read 2 more answers
PLEASE PLEASE PLEASE HELP!!
irga5000 [103]
  9            a
------  =  -----
  a            5

a^2 = 45 

a = 3<span>√5
</span>
  4            b
------  =  -----
  b            5

b^2 = 20

b = 2√5

answer: 

a = 3√5
b = 2√5

hope it helps
7 0
3 years ago
Surface Area of Cylinder=2πrh+2πr2
Alex

  • Find the surface area when r is 8 inches and h is 8 inches.

\qquad A. 160π in²

\qquad B. 154π in²

\qquad C. 288π in²

\qquad D. 256π in² ☑

We are given –

\qquad ⇢Radius of cylinder , r = 8 inches

\qquad⇢ Height of cylinder, h = 8 inches.

We are asked to find surface area of the given cylinder.

Formula to find the surface cylinder given by –

\bf \star \pink{ Surface\: Area_{(Cylinder)} = 2\pi rh +2\pi r^2 }

Now, Substitute given values –

\sf  \twoheadrightarrow  Surface\: Area_{(Cylinder)} = 2\pi rh +2\pi r^2

\sf  \twoheadrightarrow Surface\: Area_{(Cylinder)}  = 2 \pi \times 8 \times 8 + 2\pi \times 8^2

\sf  \twoheadrightarrow Surface\: Area_{(Cylinder)} = 2 \pi \times 8^2 + 2\pi \times 8^2

\sf  \twoheadrightarrow Surface\: Area_{(Cylinder)} = 2\pi \times 64 +2\pi \times 64

\sf  \twoheadrightarrow Surface\: Area_{(Cylinder)}  =128 \pi + 128\pi

\purple{\bf  \twoheadrightarrow Surface\: Area_{(Cylinder)}  = 256\pi \: in^2 }

  • Henceforth,Option D is the correct answer.

8 0
2 years ago
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