Answer:
34.87% probability that all 5 have a wireless device
Step-by-step explanation:
For each student, there are only two possible outcomes. Either they own a wireless device, or they do not. The probability of a student owning a wireless device is independent from other students. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which 
is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
81% of students own a wireless device.
This means that 
If 5 students are selected at random, what is the probability that all 5 have a wireless device?
This is P(X = 5) when n = 5. So
34.87% probability that all 5 have a wireless device
This is a number you will have memorized in grade school. If not, you can always perform long division of 2 by 3 to find it---or ask your calculator.
2/3 = 0.6666_6 . . . . . . repeating 6s indefinitely
____
Most folks get tired of writing 6s after a couple million of them, so they round it off to 0.67 or 0.667. These rounded values are NOT exactly 2/3.
Answer:
the formula for finding interest is I=p×r×t÷100
so the answer will be l=4000×3×4÷100which is equal to480.Therefore the interest is $480
Answer: I(s,t) = {(6s, 5s+6t, 5t)| sER, tER }
Step-by-step explanation:
Given the data in the question;
A vector is in the span of V1 and V2 only if it is a linear combination.
of V1 and V2.
so 'V' is in the span if;
V = SV1 + tV2 [ S and t are real numbers ]
V = [ 6si + 5sj ] + [ 6tj + 5tz]
V = 6s, 5s+6t, 5t
so
I(s,t) = {(6s, 5s+6t, 5t)| sER, tER }
5v - 4/10 = 4/5
5v = 4/5 + 4/10 = 6/5
v = (6/5)/5 = 6/25
