Answer:
Here,
n(A)={0,1,3,5,6}
n(B)={1,2,3,7}
n(AUB)=?
we know that,
AUB={0,1,2,3,5,6,7}
Step-by-step explanation:
is it okay ?
hopefully it works <3 ❣️
20,146,974. 78,901,234. 46,123,086.
76,543,218. 54,876,547
Answer and Step-by-step explanation:
Given that probability of you winning each game = 0.68
And probability of you winning next game = 0.81
Your friend's chance of winning/you losing would be = 1-0.68= 0.32
also his chance of winning next game = 0.73
To find probability that you would win the series given that you need to win two games to win the series
= probability that you win first game and second game+ probability that you win first game, lose second game and win third game + probability that you lose first game, win second game and win third game
= 0.68*0.81+0.68*0.32*0.68+0.32*0.68*0.81
=0.8750
Therefore probability that you would win the series = 0.8750
Note: here we found the probability of winning by adding(or) up the three possible combinations that would result in a win
Answer:
8
Step-by-step explanation
First you have to plug in 3 for x:
5(3-1)-2
Then using PEMDAS you would simplify that:
5(2)-2
10-2
8
Answer:
-65 i suppose
Step-by-step explanation:
