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3 years ago

8

To play at bingo night, there is a $10 cover charge plus $2 per bingo card. Write and equation for the cost (y) based on the num

ber of bingo cards (x).

1 answer:

Pani-rosa [81]3 years ago

4 0

I think it is y=10+2x

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How does solving the equation arithmetically compare to solving an equation algebraically

IRISSAK [1]

In an arithmetic equation, there is no variable in the 'meat' of the equation(example: 5-5=0). In an algebraic equation, there is a variable in the meat of the equation(example: 5-x=0).
Hope this helps and please give brainliest!

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2 years ago

The x- and Y negative coordinates have the same sign

ale4655 [162]

Answer:

if the x and y coordinates that mean that number is the solution to whatever the question is.

Step-by-step explanation:

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2 years ago

Simplify h(w)=6*2^(w-1)<br><br>Answer:<br>㏒₂(hw/6)=w-1

Alex73 [517]

Answer: log₂ $(\frac{h(n)}{6})$ + 1 = n

<u>Step-by-step explanation:</u>

h(n) = 6 * 2ⁿ⁻¹

<u> ÷6 </u> <u>÷6 </u>

$\frac{h(n)}{6}$ = 2ⁿ⁻¹

log₂ $(\frac{h(n)}{6})$ = log₂(2ⁿ⁻¹) →→<em>log₂2 cancels out</em>

log₂ $(\frac{h(n)}{6})$ = n - 1

log₂ $(\frac{h(n)}{6})+1$ = n

6 0

3 years ago

Quick Fix Inc. repairs bikes. Their revenue, in dollars, can be modeled by the equation y = 400 + 220x, where x is the number of

Sholpan [36]

The break even point is that where the total cost is equal to the total revenue. To determine the number of hours in which Quick Fix Inc. will have a breakeven, we have to equate the two equations and solve for the value of x,
400 + 220 x = 20x² + 160
The values of x from the equation are 12 and -1. Since, we do not have a negative for the number of hours, our answer is 12 hours.

5 0

2 years ago

Read 2 more answers

How many pounds of oranges do the data in the plot line represent?

Radda [10]

Answer:

OPTION C: $\textbf{37} \frac{\textbf{28}}{\textbf{8}}$ pounds.

Step-by-step explanation:

From the figure we can see that there are three dots against $3 \frac{7}{8}$ .

That means it becomes $3 \times 3\frac{7}{8}$ .

Note that if there is a mixed fraction of the form $a \frac{b}{c}$ = $a + \frac{b}{c}$ .

Therefore, $3 \times 3\frac{7}{8} = 3 \times \bigg(3 + \frac{7}{8} \bigg )$ ... (1)

Similarly, against 4 there are 2 dots.

So, it should be $4 \times 2$ pounds. ...(2)

3 dots against $4 \frac{1}{8}$ .

So, it becomes $3 \times \bigg(4 + \frac{1}{8} \bigg)$ ...(3)

Similarly, 2 dots against $4 + \frac{2}{8}$ .

This will become $2 \times \bigg( 2 + \frac{2}{8} \bigg)$ ...(4)

Now, to calculate the total pound, we simply add (1), (2), (3) & (4).

⇒ $3 \times \bigg(3 + \frac{7}{8} \bigg )$ $+$ $4 \times 2$ + $3 \times \bigg(4 + \frac{1}{8} \bigg)$ $+$ $2 \times \bigg( 2 + \frac{2}{8} \bigg)$

⇒ $9 + \frac{21}{8} + 8 + 12 + \frac{3}{8} + 8 + \frac{4}{8}$

⇒ $\bigg ( 9 + 8 + 12 + 8 \bigg) + \bigg( \frac{21 + 3 + 4}{8} \bigg )$

⇒ $\textbf{37} \textbf {+} \frac{\textbf{28}}{\textbf{8}}$ $\textbf{=} \hspace{1mm} \textbf{37} \frac{\textbf{28}}{\textbf{8}}$ which is the required answer.

5 0

2 years ago