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Alexandra [31]
3 years ago
15

Describe why the expression 2^-4 is equivalent to the expression 1/2^4

Mathematics
2 answers:
sergey [27]3 years ago
8 0

Answer:

see expression

Step-by-step explanation:

Using the rule of exponents

a^{-m} ⇔ \frac{1}{a^{m} } , then

2^{-4}

= \frac{1}{2^{4} }

Thus

2^{-4} and \frac{1}{2^{4} } are equivalent expressions

jonny [76]3 years ago
6 0

Answer:

Because when a number is raised to negative indice, it automatically becomes a fraction of 1, with the number raised to the positive indice. If the original expression becomes the other..its still equivalent and equal to the same value-just changed to make solving more easier

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An art class is making a mural for their school which has a triangle drawn in the middle. The length of the bottom of the triang
Snezhnost [94]

Answer:

4x+7

Step-by-step explanation:

x

2x+4

x+3

I hope this helps :)

6 0
3 years ago
2 intersecting lines are shown. A line with points M, H, K intersects a line with points L, H, J at point H. 4 angles are create
yulyashka [42]

Answer:

m = 10

Step-by-step explanation:

According to the picture attached, we can see the angles formed.

The angle on the top (5m+100) is sided with the angle 2m+10. This means that they are supplementary angles, their sum is 180°.

So,

5m+100+2m+10 = 180

5m+2m=180-100-10

7m = 70

m = 10

5 0
3 years ago
Read 2 more answers
Please help!? I'm soooo confused? Please help as soon as possible. It's do soon! I would really appreciate it.
Nikitich [7]
16 and 17. area is given. A=\pi  r^{2} use this relation to find radius

18.base=2, h=3.8 so, area=(1/2)*base*h=3.8 thats option D

19. area= base*h=12*7=84 option B

20.area of trapezoid= (1/2)h(a+b) where a and b are parallel sides.
so, area=(1/2)(3)(8.9+3.3)=(1/2)(3)(12.2)=3*6.1=18.3 option D

6 0
3 years ago
Select all the angles that are supplementary to 1
AlexFokin [52]

Answer: A

Step-by-step explanation:

8 0
3 years ago
Use the augmented matrix method to solve the following system of equations. Your answers may be given as decimals or fractions.
Alexandra [31]

Answer:

x\ =\ \dfrac{21}{5}

y\ =\ \dfrac{3}{5}

z = 2

Step-by-step explanation:

Given equations are

x - 2y - z = 2

x + 3y - 2z = 4

-x + 2y + 3z = 2

from the given equations the augmented matrix can be written as

\left[\begin{array}{ccc}1&-2&-1:2\\1&3&-2:4\\-1&2&3:2\end{array}\right]

R_2=>R_2-R_1\ and\ R_3=>R_3+R_1

=\ \left[\begin{array}{ccc}1&-2&-1:2\\0&5&-1:2\\0&0&2:4\end{array}\right]

R_2=>\dfrac{R_2}{5}

=\ \left[\begin{array}{ccc}1&-2&-1:2\\0&1&\dfrac{-1}{5}:\dfrac{2}{5}\\0&0&2:4\end{array}\right]

R_1=>R_1+2.R_2

=\ \left[\begin{array}{ccc}1&0&-1-\dfrac{2}{5}:2+\dfrac{4}{5}\\\\0&1&\dfrac{-1}{5}:\dfrac{2}{5}\\\\0&0&2:4\end{array}\right]

=\ \left[\begin{array}{ccc}1&0&\dfrac{-7}{5}:\dfrac{14}{5}\\\\0&1&\dfrac{-1}{5}:\dfrac{2}{5}\\\\0&0&2:4\end{array}\right]

R_3=>\dfrac{R_3}{2}

=\ \left[\begin{array}{ccc}1&0&\dfrac{-7}{5}:\dfrac{14}{5}\\\\0&1&\dfrac{-1}{5}:\dfrac{2}{5}\\\\0&0&1:2\end{array}\right]

R_1=>R_1+\dfrac{7}{5}R_3\ and\ R_2+\dfrac{1}{5}R_3

=\ \left[\begin{array}{ccc}1&0&0:\dfrac{14}{5}+\dfrac{7}{5}\\\\0&1&0:\dfrac{2}{5}+\dfrac{1}{5}\\\\0&0&1:2\end{array}\right]

So, from the above augmented matrix, we can write

x\ =\ \dfrac{21}{5}

y\ =\ \dfrac{3}{5}

z = 2

7 0
3 years ago
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