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Bogdan [553]
3 years ago
11

What are two multiples of 6 between 40 and 50

Mathematics
2 answers:
andrezito [222]3 years ago
7 0

Answer:

The two multiples are 42 and 48

6 times 7 is 42

and 6 times 8 is 48

Softa [21]3 years ago
7 0
Two multiples of 6 between 40 and 50 is 42 and 48
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QUESTION IS DOW BELOW 5 POINTS EACH PLEASE HELP PLEASE HELP PLEASE HELP
Lostsunrise [7]

a. Central angle in the circle is: Angle BAC

b. A major arc is: Arc BEC

c. A minor arc is: Arc BC

d. measure of arc BEC is: 260°

e. m(BC) = 100°

<h3>What is a Central Angle?</h3>

A central angle has two of its sides as radii of the circle, forming an angle at the center of the circle, where the vertex is at the center of the circle.

<h3>What is a Major Arc?</h3>

A major arc has a measure that is greater than 180 degrees. That is, it is more than half a circle (semicircle). Thus, measure of major arc > 180 degrees.

<h3>What is a Minor Arc?</h3>

A minor arc has a measure that is less than 180 degrees. That is, it is not more than half a circle (semicircle). Thus, measure of minor arc < 180 degrees.

a. Central angle in the circle is: Angle BAC

b. A major arc in circle A is: Arc BEC

c. A major arc in circle A is: Arc BC.

d. Measure of arc BEC = 360 - 100 [according to the central angle theorem]

Measure of arc BEC = 260°.

e. Measure of angle BAC = 100°  [given]

Measure of arc BC = angle BAC [according to the central angle theorem]

Measure of arc BC = 100°

Learn more about major and minor arcs on:

brainly.com/question/23498567

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8 0
1 year ago
Please help me, I don’t understand
White raven [17]

Answer:

73, 74, 75

Step-by-step explanation:

So the sum of three consecutive integers is 222.

Let's let the first integer be n.

Then the second integer <em>must</em> be (n+1).

And the third integer must be (n+2).

They total 222, thus:

n+(n+1)+(n+2)=222

Combine like terms:

3n+3=222

Subtract 3 from both sides:

3n=219

Divide both sides by 3:

n=73

So, the first integer is 73.

So our sequence is 73, 74, and 75.

And we're done!

5 0
3 years ago
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marusya05 [52]
Vas happenin!!

10) 2-12 -4
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12)

10 +9
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-Zayn Malik 1795
6 0
3 years ago
Tickets to a school basketball game cost $4 for students and $7 for adults. At the end of the night, 168 tickets are sold for a
stepan [7]
4s+7a=861
s+a=168

This can be solved using either elimination or substitution. I am going to use substitution.

Solve s+a=168 for s
s=168-a

Replace 168-a for s in 4s+7a=861
4(168-a)+7a=861
672-4a+7a=861

Solve for a
672+3a=861
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Substitute 63 for a in s=168-a
s=168-63=105

So, s=105 student tickets and a=63 adult tickets
3 0
3 years ago
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Citrus2011 [14]

Answer:

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2. 34 = -34

3. 0 = -0

4. 7 <u><</u> -8

5. -2 <u>></u> -4

6. 4 <u>></u> 0

7. 1 <u>></u> -1

8. -5 <u><</u> -2

9. -6 < -3 < -2 < 0

10. -5 < -1 < 2 < 8

11. a. Sapporo, Moscow, Bangor, Barrow

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3 years ago
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