Need help on number 6

Mathematics

1 answer:

vlada-n [284]3 years ago

3 0

<h3>Answer: Choice D</h3><h3>If the coach puts Tara and Laney on Team B, the mean height of the players on Team B will be shorter than 5 feet 10 inches</h3>

We know that Tara is 5 feet 9 inches. This is shorter than the mean height of team B (which is 5 feet 10 inches). Laney is some height shorter than Tara. While we don't know Laney's exact height, we know that her being shorter than 5 foot 9 inches means that the mean height will be pulled down. Tara being shorter than 5'10" means the mean goes down as well. Both new players pull the average down to a shorter height. That exact new mean isn't something we can determine as there isn't enough information; however we know in general the mean will decrease. This only works with Team B since both players are shorter than the mean here. Team A won't work because Tara is taller than the average height for this team, and its not clear where Laney's height ranks with team A.

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bazaltina [42]

$Solution, -8x>24\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x$

$Steps:$

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7 0

4 years ago

Will offer 50 points. Please answer.

Eva8 [605]

Answer:

$343\\$

Step-by-step explanation:

$\mathrm{Subtract\:the\:numbers:}\:14-7=7\\\\=\frac{7^9}{\left(\left(3+4\right)^2\right)^3}\\\\=\frac{7^9}{\left(7^2\right)^3}\\\\\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}\\\\\frac{7^9}{7^6}=7^{9-6}\\\\=343$