Answer= x³+4x²+16x+64
Expand the following:(x + 4 i) (x - 4 i) (x + 4)
(x - 4 i) (x + 4) = (x) (x) + (x) (4) + (-4 i) (x) + (-4 i) (4) = x^2 + 4 x - 4 i x - 16 i = -16 i + (4 - 4 i) x + x^2:
-16 i + (-4 i + 4) x + x^2 (4 i + x)
| | | | x | + | 4 i
| | x^2 | + | (4 - 4 i) x | - | 16 i
| | | | (-16 i) x | + | 64
| | (4 - 4 i) x^2 | + | (16 + 16 i) x | + | 0
x^3 | + | (4 i) x^2 | + | 0 | + | 0
x^3 | + | 4 x^2 | + | 16 x | + | 64:
Answer: x^3 + 4 x^2 + 16 x + 64
m∠DWC=138°, ∠AWB = 138°, ∠AWD = 42°, ∠BWC = 42°
Solution:
Line intersect at a point W.
Given .
<em>Vertical angle theorem:</em>
<em>If two lines intersect at a point then vertically opposite angles are congruent.</em>
<u>To find the measure of all the angles:</u>
∠AWB and ∠DWC are vertically opposite angles.
Therefore, ∠AWB = ∠DWC
⇒ ∠AWB = 138°
Sum of all the angles in a straight line = 180°
⇒ ∠AWD + ∠DWC = 180°
⇒ ∠AWD + 138° = 180°
⇒ ∠AWD = 180° – 138°
⇒ ∠AWD = 42°
Since ∠AWD and ∠BWC are vertically opposite angles.
Therefore, ∠AWD = ∠BWC
⇒ ∠BWC = 42°
Hence the measure of the angles are
m∠DWC=138°, ∠AWB = 138°, ∠AWD = 42°, ∠BWC = 42°.
Answer:
Colin has <em>8 sheets </em>left for his third class.
Step-by-step explanation:
Given that:
Total Number of pieces of papers =
Number of pieces of papers used for 1st class = 5 fewer than half of the pieces in the pad
Writing the equation:
Also, Given that number of pieces of papers used for the 2nd class are 2 more than that of papers used in the 1st class.
Now, number of pieces of papers left for the third class = Total number of pieces of papers in the pad - Number of pieces of papers used in the first class - Number of pieces of papers used in the first class
So, the answer is:
Colin has <em>8</em> <em>sheets </em>left for his third class.
Answer:
16.35Rs would be paid by everyone.
Step-by-step explanation:
98.10/6
=16.35Rs would be paid by everyone.
Hope it will help you :)
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