Remember, for |a|=b, assume and solve a=b and a=-b
so
first get into |a|=b form
-3|x-3|=-6
divide both sides by -3
|x-3|=2
so solve
x-3=2 and x-3=-2
add 3 to both sides
x=5 and x=1
the solutionsa re x=1 and 5
For this case we must simplify the following expression:
Then we have to start by solving the operation within the parenthesis:
ANsweer:
Answer:
Step-by-step explanation:
Let's define our variables. Let a represent the number of adult tickets sold, s represent the number of senior tickets sold, and r represent the number of senior tickets sold.
We know that a total of 350 tickets were sold. So, the number of adult, student, and senior tickets sold must total 350. Therefore, we can write the following equation:
We know that each adult ticket costs $4, each student ticket costs $2.50, and each senior ticket costs $2. We are given that a total of $1095 was collected. Therefore, the number of tickets multiplied by their respective price must equal $1095. So, we can write the following equation:
Finally, we know that 40 fewer senior tickets were sold than student tickets. So, however many students tickets were sold, we can subtract 40 to get the number of senior tickets sold. Therefore:
So, our system of equations is:
And we're done!
1. 12a²b² + -7a²b² + 9a²b²
= 14a²b² (the terms a²b² are like terms so don't look at them, just add 12 + (-7) + 9.
= 14 (ab)² (you can write like this too because both a & b are squared).
2. y² - (-5y²)
= 6y² (subtract -5 from 1, y² is the like term).