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Lerok [7]
3 years ago
10

Harold weighs 270 pounds now. If Harold goes on a diet and loses 30 pounds, then how many kilograms will he weigh?​

Mathematics
2 answers:
xxMikexx [17]3 years ago
6 0
240lbs-30lbs= 109.1lbs then you divide that by 2.2, which then equals to 49.6kg.
Leto [7]3 years ago
3 0

Answer:

108.862 kg

Step-by-step explanation:

270lb -30lb =240 lb

240 lb is approx. 108.862 Kg

(Pounds are approx 2.205 times Kg)

<em>I hope this helps! :)</em>

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The average of six positive integers starting with a is equal to b. What is the average of five consecutive integers ending with
kvasek [131]

The average of the five consecutive numbers ending with b in discuss when expressed in terms of a is; Choice D; a+3.

<h3>What is the average of five consecutive integers ending with b?</h3>

First, since it was given in the task content that the average of six positive consecutive odd integers starting with a is equal to b, it therefore follows that;

(a+a+2+a+4+a+6+a+8+a+10)/6 = b

6b=6a+30

b=a+5

Also, let the average of the consecutive intergers ending with b be denoted by; x.

(b+b-1+b-2+b-3+b-4)/5 = x

=(5b-10)/5

=b–2

The average, x=b – 2 (where b = a-5)

Ultimately, the value of the required average is; = a+5-2 = a+3.

Read more on average of integers;

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7 0
1 year ago
Plz help answer fast
spayn [35]

Answer:

d because it does not looks somlar

5 0
2 years ago
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Theorem: The segment joining the midpoints of two sides of a triangle is parallel to the third side and half its length. A two-c
natali 33 [55]

Answer:  By the slope formula.

Step-by-step explanation:

Given: ABC is a triangle (shown below),

In which A≡(6,8), B≡(2,2) and C≡(8,4)

And, D and E are the mid points of the line segments AB and BC respectively.

Prove: DE║AC and DE = AC/2

Proof:

Since, And, D and E are the mid points of the line segments AB and BC respectively.

Therefore, By mid point theorem,

coordinate of D are (\frac{2+6}{2} , \frac{2+8}{2} ) = (\frac{8}{2} , \frac{10}{2} )= (4,5)

Coordinate of E are  (\frac{2+8}{2} , \frac{2+4}{2} ) = (\frac{10}{2} , \frac{6}{2} )= (5,3)

By the distance formula,

DE=\sqrt{(5-4)^2+(3-5)^2}=\sqrt{5}

AC=\sqrt{(8-6)^2+(4-8)^2}=2\sqrt{5}

By the slope formula,

Slope of AC = \frac{4-8}{8-6} = \frac{-4}{2} = -2

Slope of DE =  \frac{3-5}{5-4} = \frac{-2}{1} = -2


            Statement                                              Reason

1. The coordinate of D are (4,5)  and           1. By the midpoint formula

the coordinate of  E are (5,3)

2. The length of DE = √5                            2. By the Distance formula

The length AC = 2√5 ⇒ Segment DE

is half the length of segment AC

3. The slope of DE = -2 and the                3. By the slope formula

slope of AC = -2

4. DE║AC                                                   4. Slopes of parallel lines are equal


7 0
3 years ago
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What of the following best describes the shape of the graph​
Assoli18 [71]

Answer:

I have no idea

Step-by-step explanation:

This question doesn't have enough information for me to answer it.

7 0
3 years ago
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Help me help me pls............
attashe74 [19]

Answer:

2

sorry i dont know but i think the answer is 2 I am not sure dont bleve me

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3 years ago
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