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shtirl [24]
3 years ago
8

How to convert binary number into decimal number​

Computers and Technology
2 answers:
Alecsey [184]3 years ago
6 0

Answer:

Multiplying by 2

Explanation:

The binary num number to decimal conversion is made by making the sum of each binary digits multiplying by 2 with raised to the power of the positional notation of digits .

Hope it is helpful to you

Liono4ka [1.6K]3 years ago
4 0

Answer:

HOW TO CONVERT BINARY INTO DECIMAL SYSTEM.

The decimal number is equal to the sum of binary digits (dn) times their power of 2 (2n):

decimal = d0×20 + d1×21 + d2×22 + ...

Example #1.SEE,

Find the decimal value of 1110012:

binary number: 1 1 1 0 0 1

power of 2: 25 24 23 22 21 20

1110012 = 1⋅25+1⋅24+1⋅23+0⋅22+0⋅21+1⋅20 = 5710

Explanation:

YOU WILL LEARN MORE IN HIGHER CLASSES.

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Rasek [7]

Answer: True

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4 0
3 years ago
Evaluate and compare free and commercial versions of the Avast antivirus software
Ivan

Answer:

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2 years ago
Every windows service has the 3 start types what are those service types?
spayn [35]

Answer:

You can stop, pause, start, delay start, or resume each service as appropriate. You can also modify the start mechanism (Manual or Automatic) or specify an account. Windows Services broadly fall into three categories depending on the actions and applications they control: Local Services, Network Services and System.

5 0
2 years ago
The energy used by an appliance which operates at 240 volts at 15 amp for 4 hr. is A. 0.92 kwhr. B. 3.45 kwhr. C. 14.4 kwhr. D.
Tju [1.3M]

Answer:

C. 14.4 kwhr.

Explanation:

To calculate the energy used by appliance first calculate the power. The formulae for calculating power(<em>P</em>) is P= I \times V, where V stands for voltage and I stands for current.

In the given problem,  V = 240 volts and I = 15 amp. Therefore,

P=240 \times 15 =3600\ watt(w) = 3.6\ kw

Now, formulae for calculating energy used i.e. work(W) is W = P\times t, where <em>t</em> is the time.

In the given question time is 4 hr. Therefore energy used will be,

Energy used (W) = 3.6\times4 =14.4\ kwhr.

8 0
4 years ago
Write an application that determines which, if any, of the following files are stored in the folder where you have saved the exe
Elza [17]

Answer:

Here is the JAVA application that determines which if any of the following files are stored in folder where you have saved the exercises created.

import java.nio.file.*;   // used to manipulate files and directories

import java.nio.file.attribute.*;  //used to provide access to file and file attributes

import static java.nio.file.AccessMode.*;  // provides access modes to test the accessibility of a file

import java.io.IOException;  //for exception handling

class FindSelectedFiles {

public static void main(String[] args) { //start of main function

   Path f1 = Paths.get("/root/sandbox/autoexec.bat"); //creates Path object f1 using Paths.get() method and this instance contains the file name and directory list used to construct the specified path

   Path f2 = Paths.get("/root/sandbox/CompareFolders.java");  //creates Path object f2 using Paths.get() method and this instance contains the file name and directory list used to construct the specified path

   Path f3 = Paths.get("/root/sandbox/FileStatistics.class");   //creates Path object f3 using Paths.get() method and this instance contains the file name and directory list used to construct the specified path

   Path f4 = Paths.get("/root/sandbox/Hello.doc"); //creates Path object f4 using Paths.get() method and this instance contains the file name and directory list used to construct the specified path

   int count=0; //used to count the number of files found  

try{  // used to define a code chunk to be tested for errors

 f1 = Paths.get("/root/sandbox/autoexec.bat");  // Converts a path string when joined form a path string to a Path

 System.out.println(f1);  //prints the file

     /* getFileSystem method is used to return the file system that created this Path object f1 and checkAccess Verifies access and throws exception if something is wrong

 f1.getFileSystem().provider().checkAccess(f1);  

 System.out.println(f1 +" File Exists\n");  //if file exists then displays this message

 count++;  }  //adds 1 to the count of number of files found

 catch (IOException e) {  //a code chunk to be executed if error occurs in the try part

  System.out.println("File Doesn't Exist\n"); }  //if file not found displays this message

   

try{  //works same as above try block but for 2nd folder and object f2

 f2 = Paths.get("/root/sandbox/CompareFolders.java");

 System.out.println(f2);

 f2.getFileSystem().provider().checkAccess(f2);

 System.out.println(f2 +" File Exists\n");

 count++;  }

 catch (IOException e) {

  System.out.println("File Doesn't Exist\n"); }

   

try{  //works same as above try block but for 3rd folder and object f3

 f3 = Paths.get("/root/sandbox/FileStatistics.class");

 System.out.println(f3);

 f3.getFileSystem().provider().checkAccess(f3);

 System.out.println("File Exists\n");

 count++; }

 catch (IOException e) {

  System.out.println("File Doesn't Exist\n"); }

   

try{  //works same as above try block but for 4th folder and object f4

    f4 = Paths.get("/root/sandbox/Hello.doc");

    System.out.println(f4);

 f4.getFileSystem().provider().checkAccess(f4);

 System.out.println(f4 +" File Exists\n");

 count++; }

 catch (IOException e) {

  System.out.println("File Doesn't Exist\n"); }

   

   System.out.println(count+" of the files exist");  }  } //displays the number of files found

Explanation:

If you want to directly pass the file name as argument to Paths.get() method then you can use the following code:

   Path f1 = Paths.get("autoexec.bat");

   Path f2 = Paths.get("CompareFolders.java");

   Path f3 = Paths.get("FileStatistics.class");

   Path f4 = Paths.get("Hello.doc");

The program determines if any, of the files from autoexec.bat, CompareFolders.java, FileStatistics.class, and Hello.doc. are stored in the folder. If a file is found then the program displays the message File exists and add 1 to the count variable each time a file is found. If all the files are found then the program returns the count as 4 otherwise the program display the number of files found by displaying the computed final value of count in the output. Lets say all the files are found then the output of the above program is:

autoexec.bat                                                                                                                                                   autoexec.bat File Exists  

                                                                                                                                                      CompareFolders.java                                                                                                                                            CompareFolders.java File Exists                                                      

                                                                                                                                                         FileStatistics.class                                                                                                                                           File Exists                                                                                        

                                                                                                                                                     Hello.doc                                                                                                                                                      Hello.doc File Exists  

   

4 of the files exist    

8 0
3 years ago
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