Here, we are required to find the area of the paper board given after the semicircle is cut out of it
Area of the paper board thatremains is 423 in²
Length = 29 in
Width = 20 in
Area of a rectangle = length × width
= 29 in × 20 in
= 580 in²
Area of a semi circle = πr²/2
π = 3.14
r = diameter / 2 = 20 in / 2 = 10 in
Area of a semi circle = πr²/2
= 3.14 × (10 in)² / 2
= 3.14 × 100 in² / 2
= 314 in²/2
= 157 in²
The semicircle is cut out of the rectangle
Find the area of the paper board that remains after the semicircle is cut out of it by subtracting the area of a semi circle from the area of a rectangle
Area of the paper board that remains = Area of a rectangle - Area of a semi circle
= 580 in² - 157 in²
= 423 in²
brainly.com/question/16994941
Answer:
or -0.25,
or -0.2,
or 0.125,
or 0.6,
or 0.75
Step-by-step explanation:
Rational numbers are any real numbers that can be written in a fraction form. So any fractional number between -0.3333 and 1.2 works.
Answer:
x = -8, 1
Step-by-step explanation:
Hi there!
![x^2+7x=8](https://tex.z-dn.net/?f=x%5E2%2B7x%3D8)
Move 8 to the other side:
![x^2+7x-8=8-8\\x^2+7x-8=0](https://tex.z-dn.net/?f=x%5E2%2B7x-8%3D8-8%5C%5Cx%5E2%2B7x-8%3D0)
Now, we can ask ourselves: what two factors of -8 add to 7? Those two numbers would be 8 and -1. Knowing this, factor:
![(x+8)(x-1)=0](https://tex.z-dn.net/?f=%28x%2B8%29%28x-1%29%3D0)
Because of the zero product property (that states that if the product of two numbers is 0, then one of the numbers must be equal to 0), we can find the solutions to the quadratic by setting each term equal to 0:
![x-1=0\\x=1](https://tex.z-dn.net/?f=x-1%3D0%5C%5Cx%3D1)
Therefore, the solutions of the quadratic are -8 and 1.
I hope this helps!
Answer: 25 hours
Step-by-step explanation:
Let r = rate, t = time
From 1st sentence,
5r x 12 = 3
60r = 3
r = 3/60 = 1/20
From the next,
4r x t = 5
4 x 1/20 x t = 5
4/20t = 5 = 25
Answer:
24
Step-by-step explanation: