We know that
The Intersecting Chord Theorem, established that "<span>When two chords intersect each other inside a circle, the products of their segments are equal."
</span>so
(n+2)*16=(n+8)*8
16n+32=8n+64
16n-8n=64-32
8n=32
n=32/8
n=4
the answer is
n=4
Senior tickets (x)
Child tickets (y)
First day: 3x + 5y = 70
second day: 12x + 12y = 216
Solve the system of equations (use elimination)
Multiply first equation by -4 -4(3x + 5y = 70), which makes it
-12x - 20y = -280
(+)12x + 12y = 216 add to second equation
-8y = -64
divide by -8. y = 8
Plugin the y value to either equation ( I will choose first equation)
3x + 5(8) =70
3x+ 40 = 70
3x = 30
x = 10
Senior tickets are $10, child tickets are $8
Answer:
10 + 10q
Step-by-step explanation:
2(5 + 5q) =
Distribute
2*5 + 2*5q
10 + 10q
Answer:
y=7x+4
Step-by-step explanation:
slope- intercept form is y=mx+c
m=7
so y=7x+c
substitute (0,4) into y=7x+c
so 4=(7x0)+c
c=4
so y=7x+4