All categories

3 years ago

Select the list that correctly includes all of the coefficients from the problem

Mathematics

1 answer:

matrenka [14]3 years ago

7 0

Answer:

( B.) 6, 1, -2 , -4

Step-by-step explanation:

A coefficient is a number multiplied by a variable. So, in this case let's take a look at the problem.

-2+6y+m-2y+8-4m

Now we have to find the numbers that have a variable next to it

which are 6,m,-2, and -4

(If you are wondering that why m is a coefficient its because it is also known as 1m)

Final answer = 6, 1, -2 , -4

Hope this helps!

You might be interested in

true or false the shortest distance from the center of the circumscribed circle to the sides of the inscribed triangle is the ci

lisov135 [29]

I think it is true but I am not 100% sure thought but good luck

6 0

3 years ago

Read 2 more answers

For what values of $x$ is $$\frac{x^2 + x + 3}{2x^2 + x - 6} \ge 0?$$ note: be thorough and explain why all points in your answe

Rus_ich [418]

To solve the inequality $\frac{x^2+x+3}{2x^2+x-6}\ge \:0$

$\mathrm{Factor\:the\:left\:hand\:side\:}\frac{x^2+x+3}{2x^2+x-6}:$

The numerator $x^2+x+3$ is not factorizable.

so factor the denominator $2x^2+x-6$ :

$2x^2+x-6=\left(2x^2-3x\right)+\left(4x-6\right)=x\left(2x-3\right)+2\left(2x-3\right)\\ \mathrm{Factor\:out\:}x\mathrm{\:from\:}2x^2-3x\mathrm{:\quad }x\left(2x-3\right)\\ \mathrm{Factor\:out\:}2\mathrm{\:from\:}4x-6\mathrm{:\quad }2\left(2x-3\right)\\$

Now take $\mathrm{Factor\:out\:common\:term\:}\left(2x-3\right)$

Then we get factor of the denominator as $\left(2x-3\right)\left(x+2\right)$

Thus $\frac{x^2+x+3}{2x^2+x-6}=\frac{x^2+x+3}{\left(x+2\right)\left(2x-3\right)}$

Now $\mathrm{Compute\:the\:signs\:of\:the\:factors\:of\:}\frac{x^2+x+3}{\left(x+2\right)\left(2x-3\right)}\\$

Signs of $x^2+x+3>0$

$\mathrm{Choosing\:ranges\:that\:satisfy\:the\:required\:condition:}\:\ge \:\:0$

$x\frac{3}{2}$ is the required solution of the given inequality.

5 0

4 years ago

Read 2 more answers

Hurry i'll give brainiest if u help me

galben [10]

X^2 = b^2-c^2
x^2= sqrt117^2-6^2
x^2=sqrt117×sqrt117-36
x^2=117-36
x^2=81
x=sqrt81
x=9cm

6 0

3 years ago

Part F

Rina8888 [55]

Answer:

my last answer is correct

Step-by-step explanation:

7 0

2 years ago

Solve the logarithmic equation. Be sure to reject any value of x that is not in the domain of the original logarithmic expressio

Sidana [21]

9514 1404 393

Answer:

x = 16/3

Step-by-step explanation:

a) The rewritten equation is ...

$\dfrac{x-2}{x+8}=\dfrac{x-1}{x+12}$

b) The solution can be found as ...

$\dfrac{x-2}{x+8}-\dfrac{x-1}{x+12}=0\\\\(x-2)(x+12)-(x+8)(x-1)=0 \qquad\text{numerator of the difference}\\\\(x^2+10x-24)-(x^2+7x-8)=0\\\\3x-16=0\qquad\text{simplified}\\\\x=\dfrac{16}{3}\qquad\text{one solution}$

The solution set is {16/3}.

_____

The applicable rule of logarithms is ...

log(a) -log(b) = log(a/b)

8 0

3 years ago

Read 2 more answers