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expeople1 [14]
3 years ago
7

Steve completed 25% of the 40 math problems that were assigned for

Mathematics
2 answers:
pentagon [3]3 years ago
7 0

Answer:

30

Step-by-step explanation:

quarter it, 25% of 40 is 1/4 so 30

shusha [124]3 years ago
5 0

Answer:

30

Step-by-step explanation:

40-25%=30

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Determine whether statement (3) follows from statements (1)
larisa [96]

Answer: Law of Detachment

Step-by-step explanation:

1) If you swim (p), you must use earplugs (q)

2) Roy swims (p)

3) Roy must use earbuds (q)

4 0
4 years ago
Lee has a jar of 100 pennies. She adds groups of 10 pennies to the jar. She adds 5 groups. What numbers does she say?
Alenkinab [10]
150 pennies in the jar .
4 0
3 years ago
Which expression is equivalent to 1.5 raised to the fifth power divided by 0.7 raised to the fourth power, all raised to the thi
zaharov [31]

The expression is equivalent to 1.5 raised to the fifth power divided by 0.7 raised to the fourth power, all raised to the third power is; Option A; 1.5 raised to the fifteenth power divided by 0.7 raised to the twelfth power

<h3>How to solve exponents?</h3>

We want to find the expression that is equivalent to 1.5 raised to the fifth power divided by 0.7 raised to the fourth power, all raised to the third power.

The sentence above can be expressed as;

((1.5⁵)/(0.7⁴))³

This can be broken down into;

[1.5^(5 * 3)]/(0.7^(4 * 3))

1.5¹⁵/0.7¹²

Looking at the options, the only correct one is;

Option A; 1.5 raised to the fifteenth power divided by 0.7 raised to the twelfth power

Read more about Exponents at; brainly.com/question/11975096

#SPJ1

3 0
2 years ago
Root 3 cosec140° - sec140°=4<br>prove that<br><br>​
Lorico [155]

Answer:

Step-by-step explanation:

We are to show that \sqrt{3} cosec140^{0} - sec140^{0} = 4\\

<u>Proof:</u>

From trigonometry identity;

cosec \theta = \frac{1}{sin\theta} \\sec\theta = \frac{1}{cos\theta}

\sqrt{3} cosec140^{0} - sec140^{0} \\= \frac{\sqrt{3} }{sin140} - \frac{1}{cos140} \\= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\

From trigonometry, 2sinAcosA = Sin2A

= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\\\=  \frac{\sqrt{3}cos140-sin140 }{sin280/2}\\=  \frac{4(\sqrt{3}/2cos140-1/2sin140) }{2sin280}\\\\= \frac{4(\sqrt{3}/2cos140-1/2sin140) }{sin280}\\since sin420 = \sqrt{3}/2 \ and \ cos420 = 1/2  \\ then\\\frac{4(sin420cos140-cos420sin140) }{sin280}

Also note that sin(B-C) = sinBcosC - cosBsinC

sin420cos140 - cos420sin140 = sin(420-140)

The resulting equation becomes;

\frac{4(sin(420-140)) }{sin280}

= \frac{4sin280}{sin280}\\ = 4 \ Proved!

3 0
3 years ago
A salesman earns a Commission of $630 for selling $3050 in merchandise
agasfer [191]

Answer:

ok so lets find what percentage 630 is of 3050

630/3050=0.20655737704

so about 20.7%

Hope This Helps!!!

7 0
3 years ago
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