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Dennis_Churaev [7]
3 years ago
13

The perimeter of a rectangle is 12 meters. If the length of the rectangle is 5 meters, what is the width (in meters)?

Mathematics
2 answers:
kicyunya [14]3 years ago
7 0

Answer:

Step-by-step explanation:

the answer is explained in the picture

emmasim [6.3K]3 years ago
6 0

Answer:

12-10=2

2/2=1

Step-by-step explanation:

5 x 2 for both sides which equals 10

12-10=2

2/2 for the two sides equal 1

so 1 I believe

lmk if u have any questions

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Can each pencil have a mass of 10.5 grams in a pack of 5 pencils weighing 60 to 95 grams?
kvasek [131]
I don't know if I'm right, but if each pencil is 10.5 grams then you multiply it by 5 ( number of pencils) and you get 52.5, which would not meet the standards of a pack weighing 60 to 95 grams.
8 0
3 years ago
In an orchard, there are 18 apple trees, 23 orange trees, and a cherry tree. What is the ratio of orange trees to cherry trees?
Nikitich [7]

Answer:

18:23

Step-by-step explanation:

18:23 (cannot be simplified further as there is no common factor)

7 0
3 years ago
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An engineer designed a valve that will regulate water pressure on an automobile engine. The engineer designed the valve such tha
IgorLugansk [536]

Answer:

Do no reject null hypothesis.  

Conclusion:

there is no sufficient statistical evidence at 0.025 level of significance to support the claim.

Step-by-step explanation:

Given that;

mean x" = 5.4

standard deviation σ = 0.7  

n = 6

Null hypothesis H₀ : μ = 5.0  

Alternative hypothesis H₁ : μ > 5.0    

∝ = 0.025    

now,

t = ( 5.4 - 5.0) / ( 0.7/√6) = 0.4 / 0.2857 = 1.4

degree of freedom df = n-1 = 6 - 1 = 5

T critical = 2.571

Therefore; t < T critical,

Do no reject null hypothesis.  

Conclusion:

there is no sufficient statistical evidence at 0.025 level of significance to support the claim.

3 0
3 years ago
A simple random sample of size nequals40 is drawn from a population. The sample mean is found to be 103.9​, and the sample stand
yan [13]

Answer:

There is enough evidence to support the claim that the population mean is greater than 100

Step-by-step explanation:

<u>Step 1</u>: We state the hypothesis and identify the claim

H_0:\mu=100 and H_1:\mu \:>\:100 (claim)

<u>Step 2</u>: Calculate the test value.

t=\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }

\implies t=\frac{103.9-100}{\frac{21.9}{\sqrt{40} } }=1.1263

<u>Step 3</u>: Find the P-value. The p-value obtained from a calculator is using d.f=39 and test-value 1.126 is 0.134

<u>Step 4</u>: We fail to reject the null hypothesis since P-value  is greater that the alpha level. (0.134>0.05).

<u>Step 5</u>: There is enough evidence to support the claim that the population mean is greater than 100.

<u>Alternatively</u>: We could also calculate the critical value to obtain +1.685 for \alpha=0.05 and d.f=39 and compare to the test-value:

The critical value (1.685>1.126) falls in the non-rejection region. See attachment.

NB: The t- distribution must be used because the population standard deviation is not known.

5 0
4 years ago
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ANTONII [103]
B.) 85

They are alternate interior angles so they are the same degree.
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3 years ago
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