The length of a rectangle is shown below:

Number 13............

topjm [15]

Multiply both sides usuinf the fraction

6 0

4 years ago

Read 2 more answers

An expression that is equivalent to 20x^4

Veronika [31]

An expression that is equivalent to $20x^4$ is 5 $x^{2}$ × 4 $x^{2}$ or 10 $x^{1}$ ×2 $x^{3}$

Step-by-step explanation:

We can write the equivalent expression for the given expression as,

5 $x^{2}$ × 4 $x^{2}$ = 20 $x^{2+2}$ = 20 $x^{4}$

We can add the powers of x as 2+ 2 = 4.

Since the base x is same we can add the powers as per the law of exponents as, $x^{m}$ × $x^{n}$ = $x^{m+n}$

10 $x^{1}$ ×2 $x^{3}$ = 20 $x^{1+3}$ = 20 $x^{4}$

So an expression that is equivalent to $20x^4$ is 5 $x^{2}$ × 4 $x^{2}$ or 10 $x^{1}$ ×2 $x^{3}$

5 0

4 years ago

Sketch a graph of y=3(x − 2)(x + 1) (x – 4) ASAPP!

Leno4ka [110]

Answer:

Use the distributive property to multiply 3 by x−2.

y=(3x−6)(x+1)(x−4)

Use the distributive property to multiply 3x−6 by x+1 and combine like terms. y=(3x 2 −3x−6)(x−4)

Use the distributive property to multiply 3x 2 −3x−6 by x−4 and combine like terms. y =3x 3 −15x 2 +6x+24

Step-by-step explanation:

I also up a link there of a graph. Please tell me if you can open it. Hope this helps! :P

5 0

3 years ago

A tractor, starting from a stationary position, drives down the road. It accelerates at 4 m/s2 for 10 seconds, then travels at a

chubhunter [2.5K]

Answer:

B. 1400 meters.

Step-by-step explanation:

According to the statement, there are two stages for the motion of the tractor, in which we need to find the travelled distance:

(i) Uniform accelerated motion.

$s_{i} = s_{o,i} +v_{o,i}\cdot t_{i} + \frac{1}{2}\cdot a\cdot t_{i}^{2}$ (1)

$v_{i} = v_{o,i}+a\cdot t_{i}$ (2)

Where:

$s_{o,i}$ - Initial position of the tractor, measured in meters.

$s_{i}$ - Final position of the tractor, measured in meters.

$v_{o,i}$ - Initial velocity of the tractor, measured in meters per second.

$t_{i}$ - Time, measured in seconds.

$a$ - Acceleration, measured in meters per square second.

$v_{i}$ - Final velocity of the tractor, measured in meters per second.

(ii) Uniform motion.

$s_{ii} = s_{i} + v_{i}\cdot t_{ii}$ (3)

Where:

$s_{ii}$ - Final position of the tractor, measured in meters.

$t_{ii}$ - Time, measured in seconds.

The distance covered by the tractor ( $\Delta s$ ), measured in meters, is:

$\Delta s = s_{ii}$ (4)

If we know that $a = 4\,\frac{m}{s^{2}}$ , $t_{i} = 10\,s$ , $v_{o,i} = 0\,\frac{m}{s}$ , $s_{o,i} = 0\,m$ and $t_{ii} = 30\,s$ , then distance covered by the tractor is:

By (1) and (2):

$s_{i} = 0\,m + \left(0\,\frac{m}{s} \right)\cdot (10\,s)+ \frac{1}{2}\cdot \left(4\,\frac{m}{s^{2}} \right) \cdot (10\,s)^{2}$

$s_{i} = 200\,m$

$v_{i} = \left(0\,\frac{m}{s} \right)+\left(4\,\frac{m}{s^{2}} \right)\cdot (10\,s)$

$v_{i} = 40\,\frac{m}{s}$

By (3):

$s_{ii} = 200\,m + \left(40\,\frac{m}{s} \right)\cdot (30\,s)$

$s_{ii} = 1400\,m$

By (4):

$\Delta s = 1400\,m$

The correct answer is B.

4 0

3 years ago

Grace loves to eat salad how many salads can she put together if she can choose one from each of the following: two types of let

Rama09 [41]

# of salads possible = 2*4*7 = 56.

6 0

3 years ago