Which line is perpendicular to the line Y = 2x +3?

The expression 3x2−5x2simplifies to −2x2<br><br> is this true?

Helga [31]

Answer:

I dont think so I would look at it as how did they get the -2

5 0

3 years ago

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A 13m long ladder when set against the well of a house reacher a height of 12m. How far is the foot of the ladder from the wall

Leokris [45]

Answer:

half a metre

Step-by-step explanation:

6 0

3 years ago

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A fitness center offers boxing classes for $15 per class and sells a set of boxing gloves for

weqwewe [10]

Answer:

8

Step-by-step explanation:

total paid: $135.95

cost of gloves: $15.95

amount for classes: $135.95 - $15.95 = $120

cost of each class: $15

number of classes: $120/$15 = 8

Answer: 8 classes

3 0

3 years ago

Explain or show how you know that 600:450, 60:45, and 4:3 are all equivalent.

saw5 [17]

600:450 divided by 10 = 60:45
60:45 divided by 15 = 4:3
so 4:3 x 15 = 60:45 x 10 = 600:450

5 0

2 years ago

The number of people arriving for treatment at an emergency room can be modeled by aPoisson process with a rate parameter of 5/h

saveliy_v [14]

Answer:

(a) The probability of having exactly four arrivals during a particular hour is 0.1754.

(b) The probability that at least 3 people arriving during a particular hour is 0.7350.

(c) The expected arrivals in a 45 minute period (0.75 hours) is 3.75 arrivals.

Step-by-step explanation:

(a) If the arrivals can be modeled by a Poisson process, with λ = 5/hr, the probability of having exactly four arrivals during a particular hour is:

$P(X=4)=\frac{\lambda^{X}*e^{-\lambda} }{X!} =\frac{5^{4}*e^{-5} }{4!}=\frac{625*0.006737947}{24} =\frac{4.211}{24}=0.1754$

The probability of having exactly four arrivals during a particular hour is 0.1754.

(b) The probability that at least 3 people arriving during a particular hour can be written as

$P(X>3)=1-P(X\leq3)=1- (P(0)+P(1)+P(2)+P(3))$

Using

$P(X)=\frac{\lambda^{X}*e^{-\lambda} }{X!}$

We get

$P(X>3)=1-P(X\leq3)=1- (P(0)+P(1)+P(2)+P(3))\\P(X>3)=1-(0.0067+ 0.0337+ 0.0842 + 0.1404 )\\P(X>3)=1-0.2650=0.7350\\$

The probability that at least 3 people arriving during a particular hour is 0.7350.

(c) The expected arrivals in a 45 minute period (0.75 hours) is

$EV=\lambda*t=5*0.75=3.75$

8 0

3 years ago