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2 years ago

Helppppp pleaseeee!!!!

Mathematics

1 answer:

Airida [17]2 years ago

7 0

It’s -2 for the first box and then 3

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Andrea is told that the means of two groups in a study were statistically significant. She knows the means and standard deviatio

salantis [7]

Answer:

Cohen's D

Step-by-step explanation:

Cohen's D is a statistic that measures effect size. It shows standardised difference between 2 means.

Effect size is defined as how large the effect of a something is or its magnitude.

Cohen's D works effectively when the sample is >50 (that is for large samples). However a correction factor can be used to make results from small samples more accurate

The formular for Cohen's D is:

D = (mean1 - mean2) ÷ (√({standard deviation1}^2 + {standard deviation 2}^2)/2)

This is the most appropriate method in the given scenario

5 0

3 years ago

How close together can two prime numbers be if they are both greater than 5? Why can they not be closer?

dalvyx [7]

Answer:

2 numbers apart (17 and 19)

Step-by-step explanation:

Eaxh other number is even, and 5, 3, and 9 are sometimes not prime. 1 is prime though.

Hope this helps!

7 0

2 years ago

6x-4y=8 solve for variable x

Radda [10]

6x - 4y = 8...solve for x
6x = 4y + 8
x = (4/6)y + 8/6
x = 2/3y + 4/3 <==

8 0

3 years ago

If a snowball melts so that its surface area decreases at a rate of 9 cm2/min, find the rate (in cm/min) at which the diameter d

zhuklara [117]

Answer:

The diameter decreases at a rate of 0.143cm/min when it is of 10 cm.

Step-by-step explanation:

Surface area of an snowball:

An snowball has spherical format. The surface area of an sphere is given by:

$S = d^2\pi$

In which d is the diameter of the sphere.

In this question:

We need to differentiate S implicitly in function of time. So

$\frac{dS}{dt} = 2d\pi\frac{dd}{dt}$

Surface area decreases at a rate of 9 cm2/min

This means that $\frac{dS}{dt} = -9$

At which the diameter decreases when the diameter is 10 cm?

This is $\frac{dd}{dt}$ when $d = 10$ . So

$\frac{dS}{dt} = 2d\pi\frac{dd}{dt}$

$-9 = 2(10)\pi\frac{dd}{dt}$

$\frac{dd}{dt} = -\frac{9}{20\pi}$

$\frac{dd}{dt} = -0.143$

Area in cm², so diameter in cm.

The diameter decreases at a rate of 0.143cm/min when it is of 10 cm.

8 0

3 years ago

Find the area of the shaded region

AlexFokin [52]

Answer:

7 $\pi$ cm²

Step-by-step explanation:

First, find the area of the big circle with the formula A = $\pi$ r²

A = $\pi$ (3)²

A = 9 $\pi$

Now, we can find the areas of the smaller circles. Since they have the same radius, they are congruent (will have the same area)

A = $\pi$ r²

A = $\pi$ (1)²

A = $\pi$

Now, we will subtract the areas of the smaller circles from the area of the big circle to find the area of the shaded region:

9 $\pi$ - $\pi$ - $\pi$ = 7 $\pi$

So, the area of the shaded region is 7 $\pi$ cm²

5 0

3 years ago