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Natalija [7]
2 years ago
7

Helppppp pleaseeee!!!!

Mathematics
1 answer:
Airida [17]2 years ago
7 0
It’s -2 for the first box and then 3
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Andrea is told that the means of two groups in a study were statistically significant. She knows the means and standard deviatio
salantis [7]

Answer:

Cohen's D

Step-by-step explanation:

Cohen's D is a statistic that measures effect size. It shows standardised difference between 2 means.

Effect size is defined as how large the effect of a something is or its magnitude.

Cohen's D works effectively when the sample is >50 (that is for large samples). However a correction factor can be used to make results from small samples more accurate

The formular for Cohen's D is:

D = (mean1 - mean2) ÷ (√({standard deviation1}^2 + {standard deviation 2}^2)/2)

This is the most appropriate method in the given scenario

5 0
3 years ago
How close together can two prime numbers be if they are both greater than 5? Why can they not be closer?​
dalvyx [7]

Answer:

2 numbers apart (17 and 19)

Step-by-step explanation:

Eaxh other number is even, and 5, 3, and 9 are sometimes not prime. 1 is prime though.

Hope this helps!

7 0
2 years ago
6x-4y=8 solve for variable x
Radda [10]
6x - 4y = 8...solve for x
6x = 4y + 8
x = (4/6)y + 8/6
x = 2/3y + 4/3 <==
8 0
3 years ago
If a snowball melts so that its surface area decreases at a rate of 9 cm2/min, find the rate (in cm/min) at which the diameter d
zhuklara [117]

Answer:

The diameter decreases at a rate of 0.143cm/min when it is of 10 cm.

Step-by-step explanation:

Surface area of an snowball:

An snowball has spherical format. The surface area of an sphere is given by:

S = d^2\pi

In which d is the diameter of the sphere.

In this question:

We need to differentiate S implicitly in function of time. So

\frac{dS}{dt} = 2d\pi\frac{dd}{dt}

Surface area decreases at a rate of 9 cm2/min

This means that \frac{dS}{dt} = -9

At which the diameter decreases when the diameter is 10 cm?

This is \frac{dd}{dt} when d = 10. So

\frac{dS}{dt} = 2d\pi\frac{dd}{dt}

-9 = 2(10)\pi\frac{dd}{dt}

\frac{dd}{dt} = -\frac{9}{20\pi}

\frac{dd}{dt} = -0.143

Area in cm², so diameter in cm.

The diameter decreases at a rate of 0.143cm/min when it is of 10 cm.

8 0
3 years ago
Find the area of the shaded region
AlexFokin [52]

Answer:

7\pi cm²

Step-by-step explanation:

First, find the area of the big circle with the formula A = \pir²

A = \pi(3)²

A = 9\pi

Now, we can find the areas of the smaller circles. Since they have the same radius, they are congruent (will have the same area)

A = \pir²

A = \pi(1)²

A = \pi

Now, we will subtract the areas of the smaller circles from the area of the big circle to find the area of the shaded region:

9\pi - \pi - \pi = 7\pi

So, the area of the shaded region is 7\pi cm²

5 0
3 years ago
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