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Mice21 [21]
3 years ago
7

Which decimal is equivalent to \dfrac{26}{9} 9 26 ​ start fraction, 26, divided by, 9, end fraction? Choose 1 answer: Choose 1 a

nswer: (Choice A) A 2.82.82, point, 8 (Choice B) B 2.\overline{8}2. 8 2, point, start overline, 8, end overline (Choice C) C 2.8892.8892, point, 889 (Choice D) D 2.92.9
Mathematics
2 answers:
trapecia [35]3 years ago
4 0

Answer: C. 2.889 .

Step-by-step explanation:

To find : A decimal expression equivalent to \dfrac{26}{9} .

When we divide 26 by 9 , we get 2.88888888889 which is approximately equal to 2.889  [Round off to the nearest thousandth place]

Hence, the decimal is equivalent to\dfrac{26}{9}  is 2.889.

Hence, the correct option is C. 2.889 .

NemiM [27]3 years ago
3 0

Answer:

2.8 with the _ above the 8 dont listen to that other guy/girl

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What is the algebraic expression for 9 less than the square root of a number?
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Answer:

4 is the square root of 2 and it's less than 9

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3 years ago
Read 2 more answers
A rectangle has perimeter 182 in. and length 52 in. what is the width
Wewaii [24]

52 multiplied by 2 then subtract it from 182 then divide the rest by 2

52x2=104     182-104=78    78/2=39   Answer:39

6 0
4 years ago
colby and jaquan are growing bacteria in an experiment in a laboratory. Colby starts with 50 bacteria in his culture and the num
kaheart [24]
To get started, we will use the general formula for bacteria growth/decay problems:

A_{f} =  A_{i} ( e^{kt} )

where: 
A_{f} = Final amount
A_{i} = Initial amount
k = growth rate constant
t = time


For doubling problems, the general formula can be shortened to:

kt = ln(2)

Now, we can use the shortened formula to calculate the growth rate constant of both bacteria:

Colby (1):
k_{1} = ln(2)/t
k_{1} = ln(2)/2 = 0.34657 per hour

Jaquan (2):
k_{2} = ln(2)/t
k_{2} = ln(2)/3 = 0.23105 per hour

Using Colby's rate constant, we can use the general formula to calculate for Colby's final amount after 1 day (24 hours).

Note: All units must be constant, so convert day to hours.

A_{f1} = 50( e^{0.34657(24)})
A_{f1} = 204,800

Remember that the final amount for both bacteria must be the same after 24 hours. Again, using the general formula, we can calculate the initial amount of bacteria that Jaquan needs:

A_{f2} = 204,800 =  A_{i2} ( e^{0.23105(24)} )
A_{i2} = 800

3 0
3 years ago
What does the factor is 3 that both 3x and 18 have in common.
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3 goes into both 3x and 18

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4 years ago
9 was subtracted from a certain number and the result was divided by 4. If the final answer is 5, what was the original number?
Ierofanga [76]

Answer:

let the number be X

Step-by-step explanation:

(x - 9)/4 = 5

or. x - 9 = 5 × 4

or. x = 20 + 9

x = 29

6 0
3 years ago
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