3. Find the equation of the line parallel to taxis

Mathematics

1 answer:

Gre4nikov [31]3 years ago

6 0

Answer:

here the answer you need

(i)passing through the point (3 ,-4)

You might be interested in

The number of a particular fish in thousands x years after 1972 can be modeled by f(x)=230(0.886)x. Estimate the year when the n

sashaice [31]

Answer:

The year is 1979.

Step-by-step explanation:

Given:

The function relating fish population and number of years since 1972 is:

$f(x)=230(0.886)^x\\Where,\ f(x)\rightarrow \textrm{fish population}\\x\rightarrow \textrm{number of years passed after 1972}$

Now, when the fish population reaches 99 thousand, it means that $f(x)=99$ . Now, plugging in $f(x)=99$ in the above equation and solving for $x$ . This gives,

$99=230(0.886)^x\\\frac{99}{230}=0.886^x\\\\\textrm{Taking natural log on both sides}\\\ln(0.886)^x=\ln(\frac{99}{230})\\\\\textrm{Using log property: }\log a^b=b\log a\\x\ln (0.886)=\ln(0.43)\\x\times (-0.12)=-0.84\\x=\frac{-0.84}{-0.12}=7\ years$

Therefore, the year after 7 years passed since 1972 is given as:

1972 + 7 = 1979.

So, the year when the number of fish reaches 99 thousand is 1979.

8 0

3 years ago

What is the parameter of interest to compare the proportions from two populations?

Marysya12 [62]

As with comparing two population proportions, when we compare two population means from independent populations, the interest is in the difference of the two means. In other words, if is the population mean from population 1 and is the population mean from population 2, then the difference is μ 1 − μ 2 .

Mark brainliest please

Hope this helps you

7 0

2 years ago

Write an equation in a point-slope form that passes through the given point with the given slope (3, 5), m = -4 and-1, 8), m = ½

4vir4ik [10]

Answer:

$\large\boxed{y-5=-4(x-3)}\\\boxed{y-8=\dfrac{1}{2}(x+1)}$