The book value of the equipment is $14000
Given,
equipment cost = $20,000
depreciation amounts = $6,000
book value of the equipment = equipment cost - depreciation cost
= 20000 - 6000
= $14000
<h3>What Are Depreciation Expenses?</h3>
Depreciation expense, on the other hand, is the amortized portion of the cost of the business's fixed assets during a certain period. Depreciation expense is recognized in the income statement as a non-cash expense that reduces the net income or profit of the business. For accounting purposes, depreciation expense is debited and accumulated depreciation is credited.
Depreciation expenses are treated as non-cash expenses because periodic monthly amortization is not involved in cash transactions.
To learn more about depreciation amounts from given link
brainly.com/question/1287985
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Answer:
y = 1/2x - 7
Step-by-step explanation:
y = mx + b
m (slope) = 1/2
x = 4
y = -5
<em>substitute</em>
-5 = 1/2 * 4 + b
-5 = 2 + b
-5 -2 = b
-7 = b
y = mx + b
y = 1/2x -7
First, the values of 2sqrt(3) or 3sqrt(3) are not even twice the length of the given base, 3.
Next, I would say that 6 is the better answer than 12, assuming that the triangle is”drawn-to-scale”.
Finally, I think the hypotenuse is 6.
Answer:
a = 8
b ≠ 18
Step-by-step explanation:
y = 4x - 7
2y = ax + b
For there to be no solution, the lines (if graphed) should be parallel meaning that their slopes are equal but the y-intercepts are different
y = mx +b is the equation of a line where m is the slope and b is the y-intercept
Multiply the first equation by 2
2y = 8x - 14
2y = ax + b
So a has to equal 8
b can be anything except 14 (otherwise the lines would be the same)
Answer:
8428
Step-by-step explanation:
According to the Question,
- Given, A theater has 56 rows of seats. If there are 13 seats in the first row, 18 in the 2nd row, 23 in the 3rd row.
We have a number sequence 13, 18, 23, ...
- We can say that this is an arithmetic sequence because of the common difference 'd', is equal to 5, and the first term 'a1' is equal to 13.
- The formula for the sum of an arithmetic sequence with n terms is given is
![S_n= \frac{n}{2} [2a_1+(n-1)d]S](https://tex.z-dn.net/?f=S_n%3D%20%5Cfrac%7Bn%7D%7B2%7D%20%5B2a_1%2B%28n-1%29d%5DS)
.
Substitute the given values into the equation to solve for the sum of the 56 rows of seats.
![S_56= \frac{56}{2}[2(13)+(56-1)(5)]\\S_{56}=28\left[26+275\right]\\S_{56}=28\left[301\right]\\S_{56}=8428](https://tex.z-dn.net/?f=S_56%3D%20%5Cfrac%7B56%7D%7B2%7D%5B2%2813%29%2B%2856-1%29%285%29%5D%5C%5CS_%7B56%7D%3D28%5Cleft%5B26%2B275%5Cright%5D%5C%5CS_%7B56%7D%3D28%5Cleft%5B301%5Cright%5D%5C%5CS_%7B56%7D%3D8428)
Therefore, there are 8428 seats in all.
