Answer:
C
Step-by-step explanation:
Now, what we know is that the total distance from the dormitory to the city is 1 if expressed in fraction. What we need to know is the fraction of the journey that is scheduled as the last part.
We can get this by subtracting the fractions of the first two phases from 1.
This goes as follows:
1 - (1/5) - (2/3) = 2/15
Now, we know that the final 8 kilometers constitute a fraction of just 2/5
Hence, we know that 2/15 of the total journey is 8 kilometers.
Let the total journey distance be T. This means that 2/15 of T is 8km
2/15 * T = 8km
T = ( 8 * 15 )/2 = 120/2 = 60km
Answer: 4.5 miles
Explanation:
When you draw the situation you find two triangles.
1) Triangle to the east of the helicopter
a) elevation angle from the high school to the helicopter = depression angle from the helicopter to the high school = 20°
b) hypotensue = distance between the high school and the helicopter
c) opposite-leg to angle 20° = heigth of the helicopter
d) adyacent leg to the angle 20° = horizontal distance between the high school and the helicopter = x
2) triangle to the west of the helicopter
a) elevation angle from elementary school to the helicopter = depression angle from helicopter to the elementary school = 62°
b) distance between the helicopter and the elementary school = hypotenuse
c) opposite-leg to angle 62° = height of the helicopter
d) adyacent-leg to angle 62° = horizontal distance between the elementary school and the helicopter = 5 - x
3) tangent ratios
a) triangle with the helicpoter and the high school
tan 20° = Height / x ⇒ height = x tan 20°
b) triangle with the helicopter and the elementary school
tan 62° = Height / (5 - x) ⇒ height = (5 - x) tan 62°
c) equal the height from both triangles:
x tan 20° = (5 - x) tan 62°
x tan 20° = 5 tan 62° - x tan 62°
x tan 20° + x tan 62° = 5 tan 62°
x (tan 20° + tan 62°) = 5 tan 62°
⇒ x = 5 tant 62° / ( tan 20° + tan 62°)
⇒ x = 4,19 miles
=> height = x tan 20° = 4,19 tan 20° = 1,525 miles
4) Calculate the hypotenuse of this triangle:
hipotenuese ² = x² + height ² = (4.19)² + (1.525)² = 19.88 miles²
hipotenuse = 4.46 miles
Rounded to the nearest tenth = 4.5 miles
That is the distance between the helicopter and the high school.
Feet, what is the angle of desperation fromax 678
We effectively rewrite the equation as
In order for the LHS to be defined, we need to restrict 
, or 
. Now, the LHS will vanish when the numerator is 0, which happens for
This value is indeed smaller than 4, so the solution is 
.
Answer:
Step-by-step explanation:
Based on the given conditions, formulate: 
Convert decimal to fraction:
Divide a fraction by multiplying its reciprocal:
Cross out the common factor: 
Calculate the product or quotient:
get the result:
Answer:
