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2 years ago

Can u help me on this... I will mark u as brilliant students.. plz

Mathematics

1 answer:

Colt1911 [192]2 years ago

8 0

Answer:

For number 5 . a= 3 and b = -1

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When Gerald started on his trip, his odometer read 109,875. At the end of his trip it read 110,480. How many miles did he travel

ozzi

Gerald traveled 605 miles. In order to get this answer you subtract 109,875 from 110,480.

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2 years ago

Please answer 20 questions i WILL MARK YOU BRAINLIEST PLEASE HELP ME 5 QUESTIONSSSSS PLEASEEE HELPPP

allochka39001 [22]

The answers should be 1D, 2C, 3B, 4A, and 5A.

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3 years ago

Read 2 more answers

Is 1/2 an irrational number?

Vinvika [58]

Answer:

Yes, 1/2 is a irrational number

Step-by-step explanation:

This is the answer because (Google research):

A number is rational if we can write it as a fraction where the numerator and denominator are both integers. However, numbers like 1/2, 46485928/2628242, and -3/7 are also rational, since they are fractions whose numerator and denominator are integers.

Hope this helps!

4 0

2 years ago

ABCD is a trapezium AD and BC are parallel

Orlov [11]

Part (a)

<h3>Answer: 12.1</h3>

-----------------------

Work Shown:

We'll apply the sine rule since we have a known opposite side of AB = 10 and an unknown hypotenuse we want to find BD.

Focus on triangle ABD

sin(angle) = opposite/hypotenuse

sin(D) = AB/BD

sin(56) = 10/x

x*sin(56) = 10

x = 10/sin(56)

x = 12.062179

x = 12.1

Make sure your calculator is in degree mode.

===================================================

Part (b)

<h3>Answer: 15.1</h3>

-----------------------

Work Shown:

Draw an xy coordinate grid.

Place point A at the origin (0,0).

Point B is 10 units above this, so B is at (0,10).

Point C is at (18,10) since we move 18 units to the right of B.

Point D is at approximately (6.745085, 0). The 6.745085 is from solving tan(56) = 10/x for x.

Refer to the diagram below.

Apply the distance formula for the points C and D.

$C = (x_1,y_1) = (18,10)\\\\D = (x_2,y_2) \approx (6.745085,10)\\\\$

$d = \text{ distance from C to D}\\\\d = \sqrt{ (x_1-x_2)^2+(y_1-y_2)^2}\\\\d \approx \sqrt{ (18-6.745085)^2+(10-0)^2}\\\\d \approx \sqrt{ 226.673112 }\\\\d \approx 15.055667\\\\d \approx 15.1\\\\$