Let
x--------> the number
we know that
11²=121
12²=144
then
x² must be greater than 121 and less than 144
case a) <span>√115
if x=</span><span>√115
then
x</span>²=115-------> is not greater than 121
case b) <span>√121
</span>if x=√121
then
x²=121-------> is not greater than 121
case c) <span>√136
</span>if x=√136
then
x²=136-------> is greater than 121 and is less than 144------> is ok
case d) <span>√150
</span>if x=√150
then
x²=150------> is not less than 144
therefore
the answer is
√136
The triangle classifies as a acute triangle.
Answer:
24-(L times 2) then divide the awnser by 2
Step-by-step explanation:
The first step to solving this problem is Multiplying In(x-1).
Answer:
(0,6)
Step-by-step explanation:
The given system of equations is
and
We substitute the first equation into the second equation to get:
We expand to get:
We group similar terms to get:
Put x=0 in to the first equation to get:
Therefore the solution is (0,6)
