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VMariaS [17]
3 years ago
7

Use compatible numbers to find two estimates

Mathematics
2 answers:
taurus [48]3 years ago
7 0
Use compatible numbers to find two estimates that the quotient is between. For example: 

1,624 divided by 3
<span> 1500 / 3 = 500 </span>

<span>1800 / 3 = 600</span>
Andreas93 [3]3 years ago
5 0
2000 / 500 = 4

4000 / 800 = 5
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The length of a rectangle is four times the width. The perimeter of the rectangle is 45 inches. Write a system of equations that
wolverine [178]

Answer:

Let l be the length and w the width of the rectangle.

P as the perimeter and A as the area.

length of a rectangle is four times the width:

w = w

l = 4w

System of equation : 2l + 2w = P

Substitute:

2(4w) + 2w = 45

8w + 2w

10w = 45

w = 45 / 10

w = 4.5

Solve for l:

l = 4w

l = 4(4.5)

l = 18

Area:

A = lw

A = 18(4.5)

A = 81 in²

8 0
3 years ago
Read 2 more answers
Jamie takes 1/4 yard strips of ribbon and cuts them into pieces that are 1/3 the length. How long are the resulting pieces of ri
AleksandrR [38]

Answer: 1/12 yards

Step-by-step explanation:

The length of the pieces originally were 1/4 yards.

Jamie then cuts them into a 1/3 of their original length.

The new length is therefore:

= Original length * proportion of original length strips are cut into

= 1/4 * 1/3

= 1/12 yards

8 0
3 years ago
327 - 184 --------- ?
Alchen [17]
327 - 184 = 143
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3 0
3 years ago
Applying Properties of Exponents In Exercise,use the properties of exponents to simplify the expression.
vitfil [10]

Answer:

(A) e^2

(b) e^{-3}

(c) e^2

(d) e^3

Step-by-step explanation:

We have given expression and we have to simplify the expression using exponent property

(A) (\frac{1}{e})^{-2}

So (\frac{1}{e})^{-2}=\frac{1}{e^{-2}}=e^2

(b) (\frac{e^5}{e^2})^{-1}

So (\frac{e^5}{e^2})^{-1}=(e^{3})^{-1}=e^{-3}

(c) \frac{e^5}{e^3}

So \frac{e^5}{e^3}=e^2

(d) \frac{1}{e^{-3}}=e^3

7 0
3 years ago
(¤_¤) help plz. I'm confused
Alex73 [517]

I know this is not an answer but, I love your handwriting!

It is soooo much neater than mine!

- Laura <3

7 0
3 years ago
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