Step-by-step explanation:
360 - 126 =234
234 ÷3x
x = 78
Answer:
see explanation
Step-by-step explanation:
the domain ( values of x ) that a quadratic can have is all real numbers
domain : - ∞ < x < ∞
the range ( values of y ) are from the vertex upwards , that is
range : y ≥ - 2
The females prefer drama movies is the correct one. The third one
Answer:
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- <u>Yes, she has enough water.</u>
Explanation:
To <em>estimate</em> the value, you can work with friendly numbers: numbers closed to the given numbers and with which you can perform easy mental calculations.
For example 4.55 may be rouned to 5, 4.85 may be rounded to 5, and 3.25 may be rounded to 3. That yields 5 + 5 + 3 = 13
Then, it seems you have about 13 liters. Is the final number equal or greater than 12 for sure?
To round 4.55 to 5 you increased the amount in 0.45, to round 4.85 to 5 you increased the amount by 0.15, and to round 3.25 to 3 you decreased the amount in 0.25.
What was the net change in your values: 0.45 + 0.15 - 0.25 = 0.60 - 0.25 = 0.35. Those are easy calculations that you can perform in your mind.
That means that you increased your total in less than 1 liter. Meaning that the final total is overestimated by 0.35, and that if you used the real amounts to make the calculations, the total will be still more than 12.
Answer:
1) (x + 3)(3x + 2)
2) x= +/-root6 - 1 by 5
Step-by-step explanation:
3x^2 + 11x + 6 = 0 (mid-term break)
using mid-term break
3x^2 + 9x + 2x + 6 = 0
factor out 3x from first pair and +2 from the second pair
3x(x + 3) + 2(x + 3)
factor out x+3
(x + 3)(3x + 2)
5x^2 + 2x = 1 (completing squares)
rearrange the equation
5x^2 + 2x - 1 = 0
divide both sides by 5 to cancel out the 5 of first term
5x^2/5 + 2x/5 - 1/5 = 0/5
x^2 + 2x/5 - 1/5 = 0
rearranging the equation to gain a+b=c form
x^2 + 2x/5 = 1/5
adding (1/5)^2 on both sides
x^2 + 2x/5 + (1/5)^2 = 1/5 + (1/5)^2
(x + 1/5)^2 = 1/5 + 1/25
(x + 1/5)^2 = 5 + 1 by 25
(x + 1/5)^2 = 6/25
taking square root on both sides
root(x + 1/5)^2 = +/- root(6/25)
x + 1/5 = +/- root6 /5
shifting 1/5 on the other side
x = +/- root6 /5 - 1/5
x = +/- root6 - 1 by 5
x = + root6 - 1 by 5 or x= - root6 - 1 by 5