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3 years ago

Pls help me! Due in like, 5 minutes and I am stuck on this question! 20 points and brainliest!

Mathematics

1 answer:

MrRa [10]3 years ago

7 0

Answer:

9 times

Step-by-step explanation:

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PLEASE HELP IM STUCK!

Rzqust [24]

Answer:

3(7+3m)=84

21+9m=84

9m=63

m=7

Step-by-step explanation:

hope it helps

7 0

3 years ago

Simplify this expression

inessss [21]

Answer:

3x^2+27y^2-18xy

Step-by-step explanation:

3(x-3y)^2

3 [(x-3y)(x-3y)]

3 [x^2-3xy-3xy+9y^2]

3 [x^2-6xy+9y^2]

open d bracket

3x^2-18xy+27y^2

rearrange

3x^2+27y^2-18xy

7 0

3 years ago

Read 2 more answers

Carole washes cars to earn money. So far, she has earned $53.95. Carole charges $8 per car for a carwash. Carole wants to attend

Norma-Jean [14]

Answer:

145.75>18

Step-by-step explanation:

you do 145.74/8 to get 18.21875 and you round it down to get 145.75>18

4 0

3 years ago

Read 2 more answers

Which of these can NOT be written as an equation?

Aleksandr [31]

Answer:

Two times t minus 6

Step-by-step explanation:

Mathematically,it is written as 2t-6

And in order for a set of characters to be written as an equation,there has to be an answer or definite result and has the "=" sign

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cint%5Climits%5E5_1%20%7B%20%5Cfrac%7BlnR%7D%7B%20R%5E%7B2%7D%20%20%7D%20%5C%2C%20dR%20"

alex41 [277]

Integrate by parts, setting

$\begin{matrix}u=\ln R&&\mathrm dv=\dfrac{\mathrm dR}{R^2}\\\mathrm du=\dfrac{\mathrm dR}R&&v=-\dfrac1R\end{matrix}$

So the integral is

$\displaystyle\int_1^5\frac{\ln R}{R^2}\,\mathrm dR=-\dfrac{\ln R}R\bigg|_{R=1}^{R=5}+\int_1^5\frac{\mathrm dR}{R^2}$
$\displaystyle\int_1^5\frac{\ln R}{R^2}\,\mathrm dR=-\left(\frac{\ln5}5-\frac{\ln1}1)-\frac1R\bigg|_{R=1}^{R=5}$
$\displaystyle\int_1^5\frac{\ln R}{R^2}\,\mathrm dR=-\frac{\ln5}5-\left(\frac15-1\right)$
$\displaystyle\int_1^5\frac{\ln R}{R^2}\,\mathrm dR=\frac15(4-\ln5)$

5 0

4 years ago