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Rzqust [24]
3 years ago
11

How many vertices AND faces does this shape have? (NO LINKS)

Mathematics
2 answers:
sleet_krkn [62]3 years ago
8 0

Answer:

It's a pyramid, therefore it must have 5 vertices

Hope this helps! Let me know if I am wrong

Step2247 [10]3 years ago
6 0
It has 5 vertices since it’s a pyaramid
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If a=2 and b=3,then ab=ba. show calculations to justify answer
Kipish [7]

if a =2 and b =3 then that would mean (2)(3)=(3)(2) so 2*3=3*2 and 2*3=6 and 3*2=6 so yes (2)(3)=(3)(2) or ab=ba

hope this helps

7 0
3 years ago
Que is on pic.i can't able to type in text.
ad-work [718]
It's not difficult to compute the values of A and B directly:

A=\displaystyle\int_1^{\sin\theta}\frac{\mathrm dt}{1+t^2}=\tan^{-1}t\bigg|_{t=1}^{t=\sin\theta}
A=\tan^{-1}(\sin\theta)-\dfrac\pi4

B=\displaystyle\int_1^{\csc\theta}\frac{\mathrm dt}{t(1+t^2)}=\int_1^{\csc\theta}\left(\frac1t-\frac t{1+t^2}\right)\,\mathrm dt
B=\left(\ln|t|-\dfrac12\ln|1+t^2|\right)\bigg|_{t=1}^{t=\csc\theta}
B=\ln\left|\dfrac{\csc\theta}{\sqrt{1+\csc^2\theta}}\right|+\dfrac12\ln2

Let's assume 0, so that |\csc\theta|=\csc\theta.

Now,

\Delta=\begin{vmatrix}A&A^2&B\\e^{A+B}&B^2&-1\\1&A^2+B^2&-1\end{vmatrix}
\Delta=A\begin{vmatrix}B^2&-1\\A^2+B^2&-1\end{vmatrix}-e^{A+B}\begin{vmatrix}A^2&B\\A^2+B^2&-1\end{vmatrix}+\begin{vmatrix}A^2&B\\B^2&-1\end{vmatrix}
\Delta=A(-B^2+A^2+B^2)-e^{A+B}(-A^2-A^2B-B^3)+(-A^2-B^3)
\Delta=A^3-A^2-B^3+e^{A+B}(A^2+A^2B+B^3)

There doesn't seem to be anything interesting about this result... But all that's left to do is plug in A and B.
3 0
3 years ago
ITEM
Hoochie [10]

Answer:

1,449

Step-by-step explanation:

8 0
3 years ago
If the original bill is $22.50, what will be the final bill after a 15% tip is paid? round to the nearest cent
Studentka2010 [4]
For this case what you should do is take 15% of 22.50 and add it to the original price. We have then:
 ((15) / (100)) * (22.50) = 3.375
 Then, we add to the original price:
 22.50 + 3.375 = 25.875
 round to the nearest cent
 25.88
 answer
 C.$25.88
7 0
3 years ago
Read 2 more answers
The distribution of red blood cell counts is different for men and women in a certain population. For both, the distribution is
Vladimir79 [104]

Answer:

a) Since the distribution is normal, the distance from the mean to the upper limit is going to be the same as the distance from the mean to the lower limit. The mean is going to be the mid point between the limits, which is going to be the average of  the limits. The limits are going to have a z score associated, in this case the upper z is 1.96 and the lower z is -1.96 as shown in the picture.

(4.4 + 6.0)/2 = 5.2

The mean for men is going to be 5.2 million cells/uL

b) The standard deviation for men can be calculated using the z score and the limit values.  The formula is shown in the picture.

σ = (6.0 - 5.2)/1.96 = 0.4

The standard deviation is 0.4 million cells/uL

6 0
4 years ago
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