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ivann1987 [24]
3 years ago
15

An insect population doubles every week. The function f(x)= 10(2)^x models the insect population after x weeks what will the pop

ulation be after 4 weeks?
A.80
B.20,000
C.160
Mathematics
1 answer:
blsea [12.9K]3 years ago
5 0

Given:

The insect population function is:

f(x)=10(2)^x

Where x is the number of weeks.

To find:

The population after 4 weeks.

Solution:

The population of insect after x weeks is given by:

f(x)=10(2)^x

We need to find the population after 4 weeks.

After substituting x=4, we get

f(4)=10(2)^4

f(4)=10(16)

f(4)=160

The population after 4 weeks is 160. Therefore, the correct option is C.

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7 0
3 years ago
What is the slope of the line graphed below??
Burka [1]

We can use the points (1, 2) and (3, -4) to solve.

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Hope This helped! Good Luck!

8 0
4 years ago
In the diagram below, ΔABC ∼ ΔDEF. If AC=18,BC=24. and DF=12, find EF
ValentinkaMS [17]

Answer:

9

Step-by-step explanation:

similar triangles.

that means there is one common factor to transform the lengths of all lines from one triangle to the other.

it looks to me DF is the longest side in DEF, and that would make it associated to BC of ABC.

so, the factor is then

BC = DF×f

24 = 12×f

=> f = 2

so, EF then is associated to AC.

AC = EF × f

18 = EF × 2

EF = 18/2 = 9

6 0
3 years ago
Average of 3,2.5,2.7​
sergeinik [125]
(3+2.5+2.7)/3 = 8.2/3 = 2.733... or 2 11/15
5 0
3 years ago
According to the Venn diagram below, what is P(A∩B∩C)?
weqwewe [10]

6

The upside down U means intersection

A intersect B intersect C is where all 3 circles overlap.

Sum up all the numbers to get 50

P (a intersect b intersect c) = 6/50 = 3/25



3 0
3 years ago
Read 2 more answers
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