The probability of getting a 2 or a getting a black card, find individual probabilities;
A standard deck has 52 cards.
There are 4 2's in a normal deck; probability of getting it is 4/25
The probability of getting a black card is; 26/52 since half the deck is red and black.
Now add up the probabilities since it says "or"
(4/52)+(26/52)=30/52 probability of the card that you were dealt being a two or a black card.
Hope I helped :)
Answer:
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Step-by-step explanation:
12/6 is 2 and the the exponents when you are dividing you just subtract. so 9-3 = 6 which makes it x^6.
Answer:
To complete the square the equation would be 2(x+4)^2-29
Answer: 31 nickels and 29 dimes
<u>Step-by-step explanation:</u>
Nickels (.05): x
Dimes (.10): y
Value: .05x + .10y = 4.45 → -20(.05x + .10y = 4.45) → -x - 2y = -89
Quantity: x + y = 60 → 1(x + y = 60) → <u> x + y </u> = <u> 60 </u>
-y = -29
y = 29
Next, substitute "29" for "y" into either equation and solve for "x":
x + y = 60
x + 29 = 60
x = 31
First you need to divide 125 / 25 which is 5 then you do subtraction 21 x 5 which is 105, then you subtract again 125 - 105 which is 20, 20 light bulbs will be broken. Or you could have just multiplied 5 by 4 which is the amount of light bulbs that were broken which is a lot easier...