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3 years ago

Find the shaded region of the figure below

Mathematics

1 answer:

lilavasa [31]3 years ago

4 0

Answer:

-x³ + 3x² - 14x + 12

Step-by-step explanation:

Area of outer rectangle = (x² + 3x - 4) * (2x - 3)

= (x² + 3x - 4) * 2x + (x² + 3x - 4) * (-3)

=x²*2x + 3x *2x - 4*2x + x² *(-3) + 3x *(-3) - 4*(-3)

=2x³ + 6x² - 8x - 3x² - 9x + 12

= 2x³ + 6x² - 3x² - 8x - 9x + 12 {Combine like terms}

= 2x³ + 3x² - 17x + 12

Area of inner rectangle = (x² - 1)* 3x

= x² *3x - 1*3x

= 3x³ - 3x

Area of shaded region = area of outer rectangle - area of inner rectangle

= 2x³ + 3x² - 17x + 12 - (3x³ - 3x)

= 2x³ + 3x² - 17x + 12 -3x³ + 3x

= 2x³ - 3x³ + 3x² - 17x + 3x + 12

= -x³ + 3x² - 14x + 12

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Plz i need the answer

Brut [27]

(a)1/10

(b)4/5

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3 years ago

Read 2 more answers

Given the coordinates below, what is the midpoint of AB? A(-6, -10) B(2,5)

madreJ [45]

Given :

$\:$

A(-6, -10)
B( 2, 5)

$\:$

$\gray{ \frak{The \: given \: two \: \: points \: are(x_{1 },y_{1})=(−6 , -10)and(x_{ 2 },y_{2} )=( 2,5 )\:}}$

$\:$

Let's solve by using midpoint formula :

$\:$

$\bf \boxed{\color{red}\frak{Midpoint \: \: Formula : {( \: x ,\:y \: ) = }( \frak{ \frac{x_{1 } + y_{1}}{2} , \frac{x_{2 } + y_{2}}{2} )}}}$

$\:$

$\large \gray{ \frak{( \: x ,\:y \: ) = }( \frak{ \frac{ -6 + 2}{2} , \frac{ - 10 + 5}{2} )}}$

$\:$

$\: \large \gray{ \frak{( \: x ,\:y \: ) = }( \frak{ \frac{ -4}{2} , \frac{ - 5}{2} )}}$

$\:$

$\large \gray{ \frak{( \: x ,\:y \: ) = }( \frak{ \cancel\frac{ -4}{2} , \cancel\frac{ - 5}{2} )}}$

$\: \:$

$\underline{ \boxed{ \large \red{ \frak{option \: d }( \frak{ - 2, - 2.5)}}}}✓$

Hope Helps! :)

6 0

2 years ago

The question is what is the distribution of the graph? explain how you know

natka813 [3]

Answer:

Pyramid Distribution

Step-by-step explanation:

I don't know the answers but from what I know it has to be pyramid distribution or triangle distribution Hope This Helps!

7 0

3 years ago

Parcc chapter 7 pythagorean theorem

Bumek [7]

So, we know that a^2 + b^2 = c^2. Right? That is called the Pythagorean Theorem.

In this case. We can say that 39 is a, 40 is b, and x is c.
NOTE: It doesn't really matter whether 39 is a or b. a & b are just the two legs of the right triangle.

So, if we say that 39 is a, 40 is b, and x is c. We can plug it into the Pythagorean Theorem.

39^2 + 40^2 = x^2

I'll let you take it from there.

7 0

3 years ago

How do you do this. Please give a full answer and explain why.

OverLord2011 [107]

Law of Exponent

$\displaystyle \large{ {a}^{ - n} = \frac{1}{ {a}^{n} } }$