Answer: so i think for part a , the first term is a subscrpit 0 which is 10. Then the formula for any term in the sequence is Ao x R ^n. So R =2 so
1st term = 10 ( 2^0)= 1
2nd term = 10 (2^1) =20
3rd term = 10 (2^2)= 40
4th = 80
5th = 160
Part B
The limit as n approaches infinity for a sub n when R is 0, 1 and 2. THE LIMIT FOR R of 0, 1 and 2 is infinity.
Part C...i will have to research...sorry
Step-by-step explanation:
Answer:
6
Step-by-step explanation:
4(3)+(2)^2-(5)^2
12+4-10
16-10
6
Let x be the length of each row.
Denver can plant 3 rows of a certain length with 2 seedlings leftover.
Total number of seeds he has = 3x+2 Denver can plant 4 rows of the same length with 3 seedling spots left empty.
Total number of seeds he has = 4x-3 Using (i) and (ii), we get= 3x+2=4x-3
Isolate variable terms: 2+3=4x-3
Answer= 5=X
Answer:

Step-by-step explanation:
in powers:
when there is x to the power of 6 to the power of 6 as an example you should multiply 6x6=36
so in this one try to do it like the one up there
6*
=3 so it is 