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eduard
2 years ago
11

How much of a radioactive kind of niobium will be left after 105 days if you start with 3,920 grams and the half-life is 35 days

?
Mathematics
1 answer:
MariettaO [177]2 years ago
3 0

Answer:

"490 grams" would be the correct solution.

Step-by-step explanation:

The given values are:

Half time,

T = 35 days

Total time,

t = 105 days

As we know,

⇒ A=A_o(\frac{1}{2} )^{\frac{t}{T} }

On substituting the values, we get

⇒     =3920\times (\frac{1}{2})^{\frac{105}{35} }

⇒     =3920\times (0.5)^3

⇒     =3920\times 0.125

⇒     =490 \ grams

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