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LenaWriter [7]
3 years ago
13

Pls help

Mathematics
1 answer:
stepladder [879]3 years ago
5 0

Answer:

Step-by-step explanation:

1-399

2  C

 3-A 99999

4a  

5b

7 b

8 C

9D

10c

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9.97793 About 10 if you rounded

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4 years ago
Read 2 more answers
What life cycle adaptation allows a seahorse to make lots of babies in a short amount of time? (2 points)
Zielflug [23.3K]

The seahorse make a lot of babies because the male carries the babies while the female makes more eggs.

<h3>What is mating?</h3>

Mating is the process in which opposite or hermaphroditic organisms pair for reproduction.

During mating between the male and female seahorse mates, the female seahorse puts her eggs in the male pouch and the male fertilises the egg in his pouch. The eggs develop into baby seahorse in the father pouch.

Find out more on mating at: brainly.com/question/922533

4 0
2 years ago
Andre and Diego were each trying to solve 2X +6 equals 3X -8 describe the first step they make to the equation
yulyashka [42]

The first step is: subtracting 6 from both sides

Step-by-step explanation:

Given equation is:

2x+6=3x-8

the given equation is a linear equation in one variable.

The simple rules to solve equations are that any operation performed on one side of the equation is also performed on other side of the equation too.

So for the given equation, in order to isolate the variable x terms on one side first of all they will subtract 6 from both sides

2x+6-6 = 3x-8-6\\2x = 3x-14

Subtracting 3x from both sides

2x-3x = 3x-14-3x\\-x = -14\\x = 14

Hence,

The first step is: subtracting 6 from both sides

Keywords: Linear equation, variables

Learn more about linear equation at:

  • brainly.com/question/763150
  • brainly.com/question/750742

#LearnwithBrainly

7 0
3 years ago
Total surface areas, length and breadth of a cuboid are 10560 cm², 60 cm and 45cm respectively, find the height of the cuboid!​
bija089 [108]

Answer:

length (l)=69 cm

breath(b)=45cm

area (a)= 10560 cm²

height (h)=?

now,

Area of cuboid =2(lb+bh+hl)

10560 cm²=2(60×45+45×h+60×h)

10560 cm²=

4 0
3 years ago
The school track has eight lanes. Each lane is 1.25 meters wide. The arc at each end of the track is 180. The distance of the ho
guajiro [1.7K]

Answer:

Part one: r5 = 41.5 m , r6 = 42.75 m , r7 = 44 m , r8 = 45.25  

Part two: Max ran 399.34 m in lane one

Part three: The distance in lanes 3 and 7 are 415.04 m and 446.46 m

Part four: Max ran in the three laps 1260.84 m around the track

Step-by-step explanation:

* lets explain how to solve the problem

- The school track has eight lanes

- Each lane is 1.25 meters wide

- The arc at each end of the track is 180° , that means the arc at each

 end is a semi-circle

- The distance of the home straight for all lanes is 85 m

- The radius of the first lane is 36.5 m

∵ The width of each lane is 1.25

∴ The radius of the second lane = 36.5 + 1.25 = 37.75

- That means the radius of each lane increased by 1.25 then the

  previous lane

∴ The radius of each lane = the radius of the previous lane + 1.25

# Part one:

∵ The radius of the 4 lane is 40.25

∴ The radius of the 5th lane = 40.25 + 1.25 = 41.5 m

∴ The radius of the  6th lane = 41.5 + 1.25 = 42.75 m

∴ The radius of the  7th lane = 42.75 + 1.25 = 44 m

∴ The radius of the  8th lane = 44 + 1.25 = 45.25 m

* r5 = 41.5 m , r6 = 42.75 m , r7 = 44 m , r8 = 45.25  

- The length of each lane is the lengths of the 2 end arcs and  2

   home straight distance

∵ The arc is a semi-circle

∵ The length of the semi-circle is πr

∴ The length of the 2 arcs is 2πr

∵ The length of the home straight distance is 85 m

∴ The length of each lane = 2πr + 2 × 85

∴ The length of each lane = 2πr + 170

# Part two:

- Max ran around lane one

∵ The radius of lane one = 36.5 m

∵ The distance of each lane = 2πr + 170

∴ The distance of lane one = 2π(36.5) + 170 = 399.34 m

* Max ran 399.34 m in lane one

# Part three:

- We will chose lanes 3 and 7

∵ The distance of each lane = 2πr + 170

∵ The radius of lane 3 = 39

∵ The radius of lane 7 is 44

∴ The distance of lane 3 = 2π(39) + 170 = 415.04 m

∴ The distance of lane 7 = 2π(44) + 170 = 446.46 m

* The distance in lanes 3 and 7 are 415.04 m and 446.46 m

# Part four:

- To find the total distance that Max ran in the 3 laps ad the answers

  in part two and part three

∵ Max ran 399.34 m in lane one

∵ Max ran 415.04 m in lane three

∵ Max ran 446.46 m in lane seven

∴ The total distance of the 3 lanes = 399.34 + 415.04 + 446.46

∴ The total distance of the 3 lanes = 1260.84

* Max ran in the three laps 1260.84 m around the track

8 0
4 years ago
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