The domain of both of these functions is all real numbers. You can input anything into f(x), and regardless, you will get 3/4. g(x) is a polynomial (specifically a quadratic), which is defined for all real numbers.
The domain of a function
is the set where both f and g are defined. Mathematically, we use ∩ for intersection to show that
<span>∩ </span>
. Here, it is just all real numbers for both g and fg.
Simple...
you have: 18-7x= -20.5
Isolate the variable x
18-7x= -20.5
18-7x= -20.5
-18 -18
-7x=-38.5
Now simply divide-->>
x=5.5
Thus, your answer.
Answer:
A = $1,025.00
I = A - P = $25.00
Equation:
A = P(1 + rt)
Calculation:
First, converting R percent to r a decimal
r = R/100 = 5%/100 = 0.05 per year.
Putting time into years for simplicity,
6 months / 12 months/year = 0.5 years.
Solving our equation:
A = 1000(1 + (0.05 × 0.5)) = 1025
A = $1,025.00
The total amount accrued, principal plus interest, from simple interest on a principal of $1,000.00 at a rate of 5% per year for 0.5 years (6 months) is $1,025.00.
Answer:
Step-by-step explanation:
In the model
Log (salary) = B0 + B1LSAT +B2GPA +B3log(libvol) +B4log(cost)+B5 rank+u
The hypothesis that rank has no effect on log (salary) is H0:B5 = 0. The estimated equation (now with standard errors) is
Log (salary) = 8.34 + .0047 LSAT + .248 GPA + .095 log(libvol)
(0.53) (.0040) (.090) (.033)
+ .038 log(cost) – .0033 rank
(.032) (.0003)
n = 136, R2 = .842.
The t statistic on rank is –11(i.e. 0.0033/0.0003), which is very significant. If rank decreases by 10 (which is a move up for a law school), median starting salary is predicted to increase by about 3.3%.
(ii) LSAT is not statistically significant (t statistic ≈1.18) but GPA is very significance (t statistic ≈2.76). The test for joint significance is moot given that GPA is so significant, but for completeness the F statistic is about 9.95 (with 2 and 130 df) and p-value ≈.0001.
All sides of this octagon seem about the same length. So, to find the perimeter, we just multiply 6 * 8 = 48 in.