3 years ago

I REALLY NEED HELP WITH THIS> ITS A RETAKE QUESTION!!!

Mathematics

1 answer:

sveticcg [70]3 years ago

3 0

Answer:

600cm^3

Step-by-step explanation:

$\frac{1}{3} {(15)}^{2} (8) \\ \frac{1}{3} (225)(8) \\ \ \frac{1800}{3} \\ 600 {cm}^{3}$

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Step-by-step explanation:

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28+7

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Step-by-step explanation:

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sesenic [268]

(8 2/3) / (2/3) = x / 1....8 2/3 miles to 2/3 hr = x miles to 1 hr
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Dahasolnce [82]

Answer:

$A_{f}=4\pi (\sqrt[3]{36} r)^{2}\\\\V_{f}=\frac{4}{3} \pi (36r^{3})$

Step-by-step explanation:

In order to find the final radii of the sphere, we need to calculate the volume, knowing that volumes are additive:

$V_{1}=\frac{4}{3} \pi (r^{3})\\\\V_{2}=\frac{4}{3} \pi (2r)^{3}\\\\V_{3}=\frac{4}{3} \pi (3r)^{3}\\\\V_{f}=\frac{4}{3} \pi (r^{3}+(2r)^{3}+(3r)^{3})\\\\V_{f}=\frac{4}{3} \pi (r^{3}+8r^{3}+27r^{3})\\\\V_{f}=\frac{4}{3} \pi (36r^{3})\\\\V_{f}=\frac{4}{3} \pi R^{3}\\\\R=\sqrt[3]{36} r$

Now that we know the radii of the new sphere, we can calculate the surface area:

$A_{f}=4\pi R^{2}\\\\A_{f}=4\pi (\sqrt[3]{36} r)^{2}$

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3 years ago

consider the sequence 11; 5; -1; -7;.... determine the sequence of the nth term of the sequence! PLSSSS HELP

STALIN [3.7K]

Answer:

Tn = 17-6n

Step-by-step explanation:

d = 5-11 = -6

Tn = a + (n-1)d = 11 + (n-1)×-6

= 11 -6n +6 = 17-6n

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3 years ago