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Natali [406]
3 years ago
6

A trip to another city is 180 miles. In miles per hour to the nearest tenth, how fast does one have to drive to average 60 mph o

n a three-hour trip during which one stops for 10 minutes? (Enter the answer in the form ab.c.)
Mathematics
1 answer:
irakobra [83]3 years ago
7 0

Answer:

63.5

Step-by-step explanation:

If one didn't take a 10 minute break he could drive 60 mph totalling 180 minutes but since he did and 180 - 10 = 170. He/she has to drive 180 miles in 170 min. so we take so we divde 180/170 and multiply by 60. If you round it to the nearest tenth you get 63.5

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Step-by-step explanation:

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3. A package of 23 medicated cough drops costs $3.00. What is the unit cost (unit rate)? O $0.11 per cough drop O $1.30 per coug
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Please help differentiate this!!!!!!!!!
vlada-n [284]
\bf h=20ln(3t+2)+30\\\\
-------------------------------\\\\
\boxed{a}\\\\
\stackrel{0~years}{t=0}\qquad h=20ln[3(0)+2]+30\implies h=20ln(2)+30
\\\\\\
h\approx 43.86
\\\\\\
\boxed{b}\\\\
\stackrel{1~meter}{h=100}\qquad 100=20ln(3t+2)+30\implies 70=20ln(3t+2)
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\cfrac{70}{20}=ln(3t+2)\implies \stackrel{\textit{log cancellation rule}}{e^{\frac{7}{2}}=e^{ln(3t+2)}}\implies e^{\frac{7}{2}}=3t+2
\\\\\\
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\bf \boxed{c}\\\\
\cfrac{dh}{dt}=20\left(\cfrac{1}{3t+2}\cdot 3  \right)+0\implies \cfrac{dh}{dt}=20\left(\cfrac{3}{3t+2} \right)\\\\\\ \cfrac{dh}{dt}=\cfrac{60}{3t+2}
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\left. \cfrac{dh}{dt}  \right|_{3}\implies \cfrac{60}{3(3)+2}\implies \cfrac{60}{11}
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\left. \cfrac{dh}{dt}  \right|_{10}\implies \cfrac{60}{3(10)+2}\implies \cfrac{15}{8}
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