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3 years ago

What is 27 to the 19th power

Mathematics

1 answer:

r-ruslan [8.4K]3 years ago

7 0

9514 1404 393

Answer:

about 1.57×10^27 (see below for the exact value)

Step-by-step explanation:

1,570,042,899,082,081,611,640,534,563

Most calculators do not carry enough internal digits to compute the exact value of this number. Fortunately, there are "infinite precision" math packages around that will find this value for you.

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If f(x) = 1/9 x - 2, what is f-1 (x)

Snowcat [4.5K]

$f(x) = \frac{1}{9} x - 2 \\$

$f( - 1) = \frac{1}{9} ( - 1) - 2 \\$

$f( - 1) = - \frac{1}{9} - 2 \\$

$f( - 1) = - \frac{1}{9} - \frac{18}{9} \\$

$f( - 1) = - \frac{19}{9} \\$

6 0

3 years ago

Consider the inequality -5(x+7)<-10 Write an inequality representing the solution for x

Naddik [55]

-5(x+7)<-10
-5x-35<-10
+35. +35
-4x<25
both divided by-4
x> -6.25
i flipped the sign because I divided with a negative number. and I hope you can make -6.25 into a fraction, I can't because I don't have a calculator with me :(

7 0

3 years ago

This Question: 1 pt

katrin2010 [14]

Answer:

No Solution.

Step-by-step explanation:

x+y=8

y=3-x

-------------

x+(3-x)=8

x+3-x=8

x-x+3=8

0+3=8

3=8

no solution

8 0

3 years ago

What is the solution to log2(2x^3-8)-2log2(x)=log2(x)

Charra [1.4K]

$\bf \textit{Logarithm of rationals}
\\\\
log_a\left( \frac{x}{y}\right)\implies log_a(x)-log_a(y)
\\\\\\
\textit{Logarithm of exponentials}
\\\\
log_a\left( x^b \right)\implies b\cdot log_a(x)\\\\
-------------------------------$

$\bf log_2(2x^3-8)-2log_2(x)=log_2(x)
\\\\\\
log_2(2x^3-8)-log_2(x^2)=log_2(x)\implies log_2\left( \cfrac{2x^3-8}{x^2} \right)=log_2(x)
\\\\\\
\textit{since both sides are getting }log_2\textit{ we can simply undo that}
\\\\\\
\cfrac{2x^3-8}{x^2}=x\implies 2x^3-8=x^3\implies x^3-8=0
\\\\\\
x^3=8\implies x=\sqrt[3]{8}\implies x=2$

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3 years ago

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Ad libitum [116K]

geez what kinda of class u in

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3 years ago

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