Answer: Infinitely many solutions
Step-by-step explanation:
Let's take the first equation.
3y + 6x = 12
Now take common,
3( y + 2x ) = 12
So, y + 2x = 4
Lets take 2nd equation
4y + 8x = 16
Take common,
4(y + 2x) = 16
So, y + 2x = 4.
Two lines with same equation have infinitely many solutions. These two equations are the same so there are infinitely many solutions.
Answer:
Carl's checked bags way 15.5 kilograms each.
Step-by-step explanation:
35-4=31 -> 31÷2=15.5
Start by placing the second equation in for Y so you have
2x+2(5+x)=10
Then distribute the 2
2x+10+2x=10
Then combine like terms
4x+10=10
Then subtract the 10 over
4x=0
Then divide the 4 and because 0 divided by 4 is 0
x=0
Then plug it back into one, Ill choose the second
y=5+0
Then add 5+0 and you get y=5
Your solution is (0,5)
Hope I Helped! :) <3
Tens. Also the answer is 40 when you divide.
The correct answer is (C). The sample is a subset of the population, and the parameter is a characteristic of the population of interest.