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Softa [21]
3 years ago
9

Give the value of x. Explain how you got your answer OR which theorem you used.

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
5 0

100+75+70+x= 360° (sum of interior angles of quadrilateral)

x= 360-245= 115°

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Solve the following system of equations: 2x + 4y − 3z = −7 3x + y + 4z = −12 x + 3y + 4z = 4
lukranit [14]

2x + 4y − 3z = −7 ---> first equation

3x + y + 4z = −12   ---> second equation

x + 3y + 4z = 4   ---> third equation

We try to eliminate z  and make two equations

Multiply first equation by 4 and second equation by 3. then add both equations

8x + 16y -12z = -28

9x + 3y +12z = -36

----------------------------

17x + 19y = -64   ---------------> equation 4

multiply third equation by -1  and add second and third equation

3x + y + 4z = −12  

-x - 3y - 4z = -4    

-------------------------------------

2x -2y = -16        ---------------> equation 5

Multiply equation 4 by 2 and equation by 19

34x + 38y = -128

38x - 38y = -304

------------------------------------

72x  = -432

Divide by 72 on both sides

x = -6

use equation 2x -2y = -16        ---------------> equation 5

2(-6) - 2y = -16

-12 -2y = -16

-2y = -4

So y = 2

Now plug in 2 for y  and -6 for x

Using any one of the three equations

x + 3y + 4z = 4  

-6 + 3(2) +4z = 4

4z = 4 (divide by 4 on both sides)

So z=1

So x= -6, y = 2  and z= 1





4 0
3 years ago
Read 2 more answers
In physics, if a moving object has a starting position at so, an initial velocity of vo, and a constant acceleration a, the
emmasim [6.3K]

Answer:

a=\frac{2S -2v_ot-2s_o}{t^2}

Step-by-step explanation:

We have the equation of the position of the object

S = \frac{1}{2}at ^2 + v_ot+s_o

We need to solve the equation for the variable a

S = \frac{1}{2}at ^2 + v_ot+s_o

Subtract s_0 and v_0t on both sides of the equality

S -v_ot-s_o = \frac{1}{2}at ^2 + v_ot+s_o - v_ot- s_o

S -v_ot-s_o = \frac{1}{2}at ^2

multiply by 2 on both sides of equality

2S -2v_ot-2s_o = 2*\frac{1}{2}at ^2

2S -2v_ot-2s_o =at ^2

Divide between t ^ 2 on both sides of the equation

\frac{2S -2v_ot-2s_o}{t^2} =a\frac{t^2}{t^2}

Finally

a=\frac{2S -2v_ot-2s_o}{t^2}

5 0
3 years ago
1/2r -3= 3 (4-3/2r) solve for r
s2008m [1.1K]

1/2r -3= 3 (4-3/2r) is to be solved for r.


I'll begin by making the assumptions that by 1/2r you actually meant (1/2)r and that by 3/2r you actually meant (3/2)r. When in doubt, please use parentheses to make your meaning clear.


Thus, 1/2r -3= 3 (4-3/2r) becomes (1/2)r -3= 3 (4-(3/2)r ) .

Simplify this by multiplying all 3 terms by 2. Doing this will eliminate the fractions:


r -6 = 3 (4*2-(3)r ) or r - 6 = 24 - 9r


Now expand the right side, using the distributive property of

r - 3 = 24 - 9r


Regrouping so as to combine like terms:


10r = 30


Solving for r: r = 30/10 = 3


The value of r that satisfies this equation is 3

8 0
3 years ago
PLEASE HELP!?!?!
nalin [4]
It’s b hope that helped have a great night
3 0
2 years ago
PLZZ HELPP ILL GIVE BRAINLIST
VashaNatasha [74]

Answer:

multiply both sides by 3

7 0
3 years ago
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