Answer:
B) always less than either of the original fractions
Step-by-step explanation:
We can easily Answer this by taking some values.
The question states that the two fractions, each have values between 0 and 1.
Let us say one of the fraction is 1/2 and the other fraction is 1/3 .
The product of the two fractions is 1/2 x 1/3 = 1/6 .
is lesser than both 1/2 and 1/3 .
So, the correct answer is that the product is always less than either of the original fractions.
F(x) = x² + x - 20 = x² + 5x - 4x - 20 = x(x + 5) - 4(x + 5) = (x + 5)(x - 4)
f(x) = 0 ⇔ (x + 5)(x - 4) = 0 ⇔ x + 5 = 0 or x - 4 = 0 ⇒ x = -5 or x = 4
Answer: C. x = -5 and x = 4.
4x=-3y+17 becomes 4x+3y=17
4x+3y=17
3x-4y=-6
alrighty
elimination
muliply first equation by 4 and 2nd by 3 and add them
16x+12y=68
9x-12y=-18
add them
25x+0y=50
25x=50
idivide both sides by 25
x=2
sub back
3x-4y=-6
3(2)-4y=-6
6-4y=-6
-4y=-12
y=3
(x,y)
(2,3)
