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3 years ago

Five taken from a number squared.

Mathematics

1 answer:

Mrrafil [7]3 years ago

6 0

The solution starts with solving the word problem which turns out to be (x-5)^2. The image helps

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How do you simplify a fraction with a denominator of a variable like this 6x/x

Georgia [21]

Step-by-step explanation:

The x's will simply cancel each other out and you will be left with a 6

hope it makes sense

6 0

2 years ago

Add. Write your answer in simplest form. 2 5/6 + 3 2/5

castortr0y [4]

Answer:

187/85 or in decimal form 2.2

Step-by-step explanation:

Make it a mixed fraction then find the common denominator

8 0

2 years ago

Please solve asap thanks

tensa zangetsu [6.8K]

I think..

A' =( -1,-4 )

B' = ( 3,-2 )

C'=( - 2, 2 )

5 0

2 years ago

Read 2 more answers

Evaluate 12^2 1. 144 2. 24 3. 266

pogonyaev

Answer:

The answer is 144

Step-by-step explanation:

12*12

12²

144

6 0

2 years ago

This is really confusing me: Simplify so that your answers contain only positive exponents.

xxTIMURxx [149]

Answer:

see below

Step-by-step explanation:

For simplifying expressions of this sort, there are four rules of exponents that come into play;

$a^ba^c=a^{b+c}\\\\(ab)^c=a^cb^c\\\\(a^b)^c=a^{bc}\\\\\dfrac{1}{a^b}=a^{-b}\ \quad\text{which means}\quad a^b=\dfrac{1}{a^{-b}}$

I find it convenient to eliminate the fractions by adding the exponents, then rewrite any negative exponents as denominator factors.

$23. \quad\dfrac{1}{x^{-2}}=x^2\\\\24. \quad\dfrac{mn}{m^2n^3}=m^{1-2}n^{1-3}=m^{-1}n^{-2}=\dfrac{1}{mn^2}\\\\25. \quad\dfrac{k^{-2}}{k^{-3}}=k^{-2-(-3)}=k\\\\26. \quad\left(\dfrac{m^2}{n^3}\right)^3=\dfrac{m^{2\cdot 3}}{n^{3\cdot 3}}=\dfrac{m^6}{n^9}\\\\27. \quad\dfrac{x^2y^3z^4}{x^{-3}y^{-4}z^{-5}}=x^{2-(-3)}y^{3-(-4)}z^{4-(-5)}=x^5y^7z^9$

3 0

3 years ago