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Alja [10]
3 years ago
11

It’s just a multiple choice question about emails

Computers and Technology
2 answers:
cestrela7 [59]3 years ago
7 0
The Answer is : A, B , C .
Lapatulllka [165]3 years ago
7 0
A, b, and c! Do u think in could get brainliest from you? I’m sorry for asking I wanted to know what it’s like but I hope u have an amazing day!
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Which encryption standard uses Advanced Encryption Standard (AES), a 128-bit block cipher that is much tougher to crack than the
Alchen [17]

Answer:

Wi-Fi Protected Access 2 (WPA2)

Explanation:

The Wi-Fi Protected Access 2 (WPA2) makes some alterations to the encryption algorithm that were used in WPA and WEP to what is known as the  Advanced Encryption Standard (AES). This is a 128-bit block cipher considered to be much more difficult to crack than the usual 128-bit TKIP wrapper. However, although WPA2 offers a much more tougher encryption standard, it is important to note that it is not hack proof.

5 0
3 years ago
When someone asks, Is this information specific enough?, he or she is interested in more _____.
AVprozaik [17]

Answer:

precision

Explanation:

In simple English precise means exact or something specific

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3 years ago
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What are the main techniques used to help manage test anxiety? Check all that apply.
Aleks04 [339]

Answer:

1) Avoid the perfectionist of trap

2)Banish the negative thoughts

3) Get enough sleep

4) Make sure you are prepared

5) take deep breaths

Explanation:

In my thought it's the answer of this question.

4 0
3 years ago
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Calculate the shear stress (lbf/in^2) for a given normal stress (lbf/in^2) that is applied to a material with a given cohesion (
LenaWriter [7]

MOHR-COULOMB FAILURE CRITERIA:

In 1900, MOHR-COULOMB states Theory of Rupture in Materials which defines as “A material fails due to because of a critical combination of normal and shear stress, not from maximum normal or shear stress”. Failure Envelope is approached by a linear relationship.

If you can not understand the below symbols see the attachment below

 f   f ()  

Where:      f = Shear Stress on Failure Plane  

       ´= Normal Stress on Failure Plane

 See the graph in the attachment

For calculating the shear stress, when Normal stress, cohesion and angle of internal friction are given. Use this formula:   shear stress =  f  c   tan 

Where,  

• f  is Shear Stress on Failure Plane

• c  is Cohesion

•  is Normal Total Stress on Failure Plane

•  is Friction Angle

8 0
4 years ago
Kiara is using her software's graphic formats to create a line graph. As she
Ad libitum [116K]

Correct the data she entered , and the software will adjust the graph -apex

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3 years ago
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