1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dem82 [27]
3 years ago
12

Divide the following:​

Mathematics
1 answer:
Ray Of Light [21]3 years ago
6 0

Answer:

Here. Solved. Check the answer.

You might be interested in
Use a graph in a (-2π, 2π, π/2) by (-3, 3, 1) viewing rectangle to complete the identity.
yaroslaw [1]

First, notice that:

2\tan (\frac{x}{2})=2\cdot(\pm\sqrt[]{\frac{1-cosx}{1+\cos x})}

And in the denominator we have:

1+\tan ^2(\frac{x}{2})=1+\frac{1-\cos x}{1+\cos x}=\frac{1+cosx+1-\cos x}{1+cosx}=\frac{2}{1+\cos x}

then, we have on the original expression:

\begin{gathered} \frac{2\tan(\frac{x}{2})}{1+\tan^2(\frac{x}{2})}=\frac{2\cdot\pm\sqrt[]{\frac{1-\cos x}{1+cosx}}}{\frac{2}{1+\cos x}}=\frac{2\cdot(\pm\sqrt[]{1-cosx})\cdot(1+\cos x)}{2\cdot(\sqrt[]{1+cosx})} \\ =(\sqrt[]{1-\cos x})\cdot(\sqrt[]{1+\cos x})=\sqrt[]{(1-\cos x)(1+\cos x)} \\ =\sqrt[]{1-\cos^2x}=\sqrt[]{\sin^2x}=\sin x \end{gathered}

therefore, the identity equals to sinx

8 0
1 year ago
HELP PLEASE I WILL MARK YOU AS A BRAINLIEST!!
Naddika [18.5K]

Answer:

C

Step-by-step explanation:

4x-8

Hope I helped. Please mark brainliest. Have a good day!

5 0
3 years ago
Kurt has $20. He spends $8. What percent of his money did Kurt spend?
wlad13 [49]

Answer:

40% Hope I helped

7 0
3 years ago
Read 2 more answers
PLEASE HELP MEEEEEEEEEE
Alona [7]

Answer:

15

Step-by-step explanation:

<em>here's </em><em>your</em><em> solution</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>Both </em><em>the </em><em>traingle</em><em> </em><em>are </em><em>similar</em><em> </em><em>hence </em><em>,</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>it's</em><em> </em><em>corresponding</em><em> </em><em>sides</em><em> </em><em>are </em><em>in </em><em>equal </em><em>ratio</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>so,</em><em>8</em><em>/</em><em>2</em><em>0</em><em> </em><em>=</em><em> </em><em>6</em><em>/</em><em>y </em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>8</em><em>y</em><em> </em><em>=</em><em> </em><em>2</em><em>0</em><em>*</em><em>6</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>y=</em><em> </em><em>2</em><em>0</em><em>*</em><em>6</em><em>/</em><em>8</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>y </em><em>=</em><em> </em><em>1</em><em>5</em>

<em> </em><em> </em><em> </em><em> </em><em>hope</em><em> it</em><em> helps</em>

4 0
3 years ago
Help, please I can't answer it
Ivan

Answer:

A and c i think it will help you

5 0
3 years ago
Other questions:
  • mukul has $2.25 in nickerl,dimes and quarters. he has 6 more times than quarters and 9 more nickels than quarters. How manyof ea
    9·1 answer
  • What is the answer for 3,4,5,6 and 7?
    10·1 answer
  • How many whole 3/16 foot sections are in the 11/12 foot wooden board
    8·1 answer
  • Use π = 3 19. Calculate the area of a circle with diameter of 14cm
    5·2 answers
  • I HAVE NO IDEA - Please show your work and full explanation! <br><br> Thanks !
    5·2 answers
  • What is the depth of the soup ( the area shaded) 20cm is the diameter?
    14·1 answer
  • Wat iz dis bul crup
    12·1 answer
  • HELP PLSSS Function g is a transformation x of f(x) = 2 ^ x Select all the true statements about the functions. (F-|F.2.4)
    12·1 answer
  • Work out m and c for the line:y=3x-2
    9·1 answer
  • At the beginning of each school year, every grade level must elect a president, treasurer, and secretary. If the sophomore class
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!