The answer is <span>20.3896551724</span>
Answer:
t = 0.293 s and 14.52 s
Step-by-step explanation:
The heights of the ball in feet is given by the equation as follows :
![S = -2.7t^2+40t+6.5](https://tex.z-dn.net/?f=S%20%3D%20-2.7t%5E2%2B40t%2B6.5)
Where t is the number of seconds after the ball was thrown.
We need to find is the ball 18 ft above the moon's surface.
Put S = 18 ft
![-2.7t^2+40t+6.5=18\\\\-2.7t^2+40t=18-6.5\\\\-2.7t^2+40t-11.5=0](https://tex.z-dn.net/?f=-2.7t%5E2%2B40t%2B6.5%3D18%5C%5C%5C%5C-2.7t%5E2%2B40t%3D18-6.5%5C%5C%5C%5C-2.7t%5E2%2B40t-11.5%3D0)
It is a quadratic equation. Its solution is given by :
![t=\dfrac{-40+\sqrt{40^{2\ }-4\left(-2.7\right)\left(-11.5\right)}}{2\left(-2.7\right)},\dfrac{-40-\sqrt{40^{2\ }-4\left(-2.7\right)\left(-11.5\right)}}{2\left(-2.7\right)}\\\\t=0.293\ s,14.52\ s](https://tex.z-dn.net/?f=t%3D%5Cdfrac%7B-40%2B%5Csqrt%7B40%5E%7B2%5C%20%7D-4%5Cleft%28-2.7%5Cright%29%5Cleft%28-11.5%5Cright%29%7D%7D%7B2%5Cleft%28-2.7%5Cright%29%7D%2C%5Cdfrac%7B-40-%5Csqrt%7B40%5E%7B2%5C%20%7D-4%5Cleft%28-2.7%5Cright%29%5Cleft%28-11.5%5Cright%29%7D%7D%7B2%5Cleft%28-2.7%5Cright%29%7D%5C%5C%5C%5Ct%3D0.293%5C%20s%2C14.52%5C%20s)
So, the ball is at first 0.293 s and then 14.52 s above the Moon's surface.
Answer:
y = 2 and y = -5
Step-by-step explanation:
Because the coefficient is not greater than 1, you can simply solve the problem without the quadratic formula.
By using the "x" method, you must figure out what multiplies to give you -10, and adds to give you 3
So, you find your values as 5 and -2. You then set these values equal to zero in terms of Y. As so---- (y+5)=0 and (y-2)=0
Then, you solve out to get your answer! Y is equal to -5 and 2
Answer:
the triangles are reflected across the line y= -x
hope this helps
Step-by-step explanation: