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bazaltina [42]
3 years ago
14

For the sequence an = an-1 + an-2 and ai = 2, a2 = 3,

Mathematics
1 answer:
loris [4]3 years ago
3 0

Answer:

a_1 = 2

a_2 = 3

a_3 = 5

a_4 = 8

a_5 = 13

Step-by-step explanation:

Given

a_n = a_{n-1} + a_{n-2}

a_1 = 2

a_2 = 3

Solving (a): The first term

This has already been given as:

a_1 = 2

Solving (b): The second term

This has already been given as:

a_2 = 3

Solving (c): The third term

This is calculated as:

a_n = a_{n-1} + a_{n-2}

a_3 = a_{3-1} +a_{3-2}

a_3 = a_2 +a_1

a_3 = 3 +2

a_3 = 5

Solving (d): The fourth term

This is calculated as:

a_n = a_{n-1} + a_{n-2}

a_4 = a_{4-1} +a_{4-2}

a_4 = a_3 +a_2

a_4 = 5+3

a_4 = 8

Solving (e): The fifth term

This is calculated as:

a_n = a_{n-1} + a_{n-2}

a_5 = a_{5-1} +a_{5-2}

a_5 = a_4 +a_3

a_5 = 8+5

a_5 = 13

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Answer:

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Step-by-step explanation:

We know that A function is a certain relationship is defined as having only one corresponding y-value for each x-value.

Considering the function

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It is clear from the table that the function has only one corresponding y-value for each x-value. In other words, there is no repetition of 'x' value.

Therefore, we conclude that a function is defined as having only one corresponding y-value for each x-value.

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3 years ago
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Answer:

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Step-by-step explanation: See Annex

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(x/2)² = 2*x

x²/4 = 2*x

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Then point  P ( 8 ;  4 )

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From these  two points, we get the integration limits for dy ( 0 , 4 )are the integration limits.

Now with the help of geogebra we have: In the annex segment ABCD is dy then

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V = π * [(4/3)y³ - (1/20)y⁵] |₀⁴

V =  π * [ (4/3)*4³ - 0 - 1/20)*1024 + 0 )

V = π * [256/3  - 51,20]

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