Odd integers are represented by 2n+1 where n is a whole number
consecutive odd are 2 apart so
they are 2n+1 and 2n+1+2
the sum of them is at least 16
2n+1+2n+1+2<u>></u>16
4n+4<u>></u>16
minus 4
4n<u>></u>12
divide 4
n<u>></u>3
sub back
2n+1 and 2n+3
2(3)+1 and 2(3)+3
6+1 and 6+3
7 and 9
they have to be at least 7 and 9
I am assuming you want to solve for x:-
Now cosec^2 2x = 1 - cot^2 2x so the equation becomes
3 cosec^2(2x) + 2 cosec 2x = cosec^2 2x
2 cosec^2 2x + 2 cosec 2x = 0
2 cosec 2x ( cosec 2x + 1) = 0
so 2 cosec 2x = 0 or cosec 2x = -1
cosec 2x = 0 or cosec 2x = -1
cosec 2x = 0 is indeterminate so we ignore the first one
cosec 2x = -1 can be written as 1 / sin 2x = -1
so sin 2x = -1
giving 2x = 270 degrees
Therefore x = 135 degrees answer
Given:
The function f represents the diver's distance from sea level over time, in seconds.
To find:
The correct statement for the domain.
Solution:
Domain is the set of input values for which the function is defined.
Here, x values are the input values and they represent time intervals on which the function is defined
Here, the possible intervals for x are 
.
![Domain=(-9,-2]\cup (-2,1]\cup (1,7)](https://tex.z-dn.net/?f=Domain%3D%28-9%2C-2%5D%5Ccup%20%28-2%2C1%5D%5Ccup%20%281%2C7%29)
Therefore, the domain is the time interval (−9, 7). Hence the correct option is A.
Yes I do agree but that is he d dit-on
Answer:
The median weight for shelter A is greater than that for shelter B.
The data for shelter B are a symmetric data set.
The interquartile range of shelter A is greater than the interquartile range of shelter B.
