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Crazy boy [7]
3 years ago
8

How can you make a search phrase more effective?

Computers and Technology
1 answer:
Rufina [12.5K]3 years ago
5 0

Answer:

Keep it short: The fewer words you use, the more accurate your search will be. ...

Use quotes: Double quotes around a set of words tells gog.le to consider the exact words in that exact order without any change.

Search a web site: allows you to specify that your search results must come from a given website.

Explanation:

You might be interested in
Which of the following is a tip for making sure you are messaging safely?
dimaraw [331]

Answer:

B.

Explanation:

You have to be careful about the people you talk too, because, if you don't, you can be in real danger.

sorry if I am wrong

8 0
3 years ago
write a program that first asks the user to enter three real numbers using GUI input. Print the sum if all three numbers are pos
den301095 [7]

Answer:

Here is the complete program:

import javax.swing.JOptionPane;  //to use GUI in JAVA application

import java.util.Scanner;  //to take input from user at console

public class Main {

public static void main(String[] args) {  //start of main function body

 String num1, num2,num3;  //declare three variables to store strings of numbers for input dialog

 double number1, number2, number3, sum,product; //declare three double type variables to hold the real numbers  

 num1 = JOptionPane.showInputDialog("num1");  //shows a dialog box prompting user to enter value of first number i.e. num1

 number1 = Double.parseDouble(num1);  //scans and reads the value of first input number i.e. number1    

 num2 = JOptionPane.showInputDialog("num2");  //shows a dialog box prompting user to enter value of second number i.e. num2

 number2 = Double.parseDouble(num2);   //reads number2  

               num3 = JOptionPane.showInputDialog("num3");  //shows a dialog box prompting user to enter value of third number i.e. num3

 number3 = Double.parseDouble(num3);   //reads number3  

   if(number1>0&& number2>0 && number3>0){  //checks if all three numbers are positive

   sum = number1 + number2+ number3;  //displays the sum by adding all three positive numbers

   JOptionPane.showMessageDialog(null, "the sum is : " + sum , "Results", JOptionPane.PLAIN_MESSAGE );      }   // displays the result of sum in a message dialog box

 

    if(number1<0 && number2>0 && number3>0)      {  //checks if number2 and number3 are positive

   product = number2*number3;  //computes product

   JOptionPane.showMessageDialog(null, "the product is : " + product , "Results", JOptionPane.PLAIN_MESSAGE );      }  //displays the result

   else if (number2<0&&number1>0&&number3>0){  //checks if number1 and number3 are positive

    product = number1*number3;  //computes product

JOptionPane.showMessageDialog(null, "the product is : " + product , "Results", JOptionPane.PLAIN_MESSAGE );      }  //displays the result

   else if (number3<0 && number1>0 && number2>0)     {  //checks if number1 and number2 are positive

     product = number1*number2;  //computes product of 2 positive numbers

     JOptionPane.showMessageDialog(null, "the product is : " + product , "Results", JOptionPane.PLAIN_MESSAGE );      }  //displays the result

   else     {  /.if all the numbers are positive.

/*However this part is optional. You can just use else part for above else if statement and exclude this else part. In this way the product of all three positive numbers is not computed and product is only computed when only two numbers of the three are positive */

     product = number1*number2*number3;  //computes product of all three positive numbers

     JOptionPane.showMessageDialog(null, "the product is : " + product , "Results", JOptionPane.PLAIN_MESSAGE );      }   //displays the result

Scanner scan = new Scanner(System.in);  //creates a Scanner class object

double value1 , value2, quotient;  //declares variables to hold the values of two real numbers and the result of division of the two real numbers is stored in quotient variable

System.out.println("Enter the first real number: ");  //prompts user to enter the value of first real number from the console

value1 = scan.nextDouble();  //reads the first number from user

System.out.println("Enter the second real number : ");  //prompts user to enter the value of second real number from the console

value2 = scan.nextDouble();  //reads the second number from user

if(value1<0&&value2<0)  {  //checks if both the numbers are negative

quotient = value1/value2;  //compute the quotient

JOptionPane.showMessageDialog(null, "the quotient is : " + quotient , "Results", JOptionPane.PLAIN_MESSAGE );    }  //displays result

 else  //if both numbers are not negative

JOptionPane.showMessageDialog(null, "Both numbers are not negative" );   //displays this message in a dialog box

  }  }

Explanation:

In the above given code if you want to display the outputs in console then alter the following statements as follows:

   if(number1>0&& number2>0 && number3>0){

   sum = number1 + number2+ number3;

  System.out.println("the sum is :  " + sum); }      

 

    if(number1<0 && number2>0 && number3>0)      {

    product = number2*number3;

      System.out.println("the product is :  " + product); }          

   else if (number2<0&&number1>0&&number3>0){

          product = number1*number3;

System.out.println("the product is :  " + product);      }

   else if (number3<0 && number1>0 && number2>0)     {

     product = number1*number2;

     System.out.println("the product is :  " + product);     }

   else     {

     product = number1*number2*number3;

      System.out.println("the product is :  " + product);      }

Scanner scan = new Scanner(System.in);

double value1 , value2, quotient;

System.out.println("Enter the first real number: ");

value1 = scan.nextDouble();

System.out.println("Enter the second real number : ");

value2 = scan.nextDouble();

if(value1<0&&value2<0)  {

quotient = value1/value2;

 System.out.println("the quotient is :  " + quotient);   }

 else  

System.out.println("Both numbers are not negative");

Notice that all the JOptionPane.showMessageDialog statement are changed with System.out.println which prints the results on the console.

4 0
4 years ago
Why AI strategy is important?
Nezavi [6.7K]

AI strategy is important because it will help you to focus on your core business objectives and prioritize ways that AI can help deliver those business goals.

Business operations become more consistent, swift, and scalable thanks to automation, which also reduces costs. Some Accenture clients report time savings of up to 70%. But what makes it even more intriguing is its capacity to spur economic expansion. When compared to businesses that are still in the pilot stage, those that scale successfully receive a 3X return on their AI investments. It makes sense that 84 percent of C-suite executives think they need to use AI to meet their growth goals. With a steady stream of insights to fuel innovation and competitive advantage in a world of perpetual upheaval, AI enables firms to respond quickly. Scaling up it can make it a vital facilitator of your strategic aims and even a necessity for survival.

To learn more about Business click here:

brainly.com/question/15826771

#SPJ4

7 0
1 year ago
The operating system, and in particular the scheduler, is not an important component of a real-time system.
Gnoma [55]
This is false. The scheduler is an important component of a real-time system.
3 0
3 years ago
Which of the following is an example of a wanted versus I need
Svetlanka [38]
B. cable tv. Everyone can live without tv
you need food and shelter to live and insurance is more necessary than tv
4 0
4 years ago
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